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# Andy has half as many books as Bill, who has one third as many books

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Joined: 21 Jun 2014
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Concentration: General Management, Technology
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WE: Information Technology (Computer Software)
Andy has half as many books as Bill, who has one third as many books  [#permalink]

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14 Oct 2017, 07:21
3
00:00

Difficulty:

25% (medium)

Question Stats:

86% (01:42) correct 14% (01:58) wrong based on 41 sessions

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Andy has half as many books as Bill, who has one third as many books as charlie. which of these can be total number of books three of them have?

(A) 30
(B) 60
(C) 90
(D) 120
(E) 150

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Joined: 22 May 2017
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Re: Andy has half as many books as Bill, who has one third as many books  [#permalink]

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14 Oct 2017, 07:51
1
1
My approach
assume 3 variables
Andy - a
Bill - b
charlie - c

a= 1/2 b -----> i.e b=2a
b= 1/3 c -----> i.e c=3b = 3*2a = 6a

Total = a + b + c
= a + 2a + 6a
=9a

hence the total should be divisible by 9
only option is 90 Hence C

Just have a query what if 2 options are divisible by 9
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Joined: 10 Jun 2016
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Location: India
Concentration: Operations, Strategy
GMAT 1: 710 Q49 V37
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Re: Andy has half as many books as Bill, who has one third as many books  [#permalink]

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14 Oct 2017, 08:04
1
Let A has X books. Therefore, B has 2X books, since number of books with A is half that of B.

In the same vein, number of books with C is thrice that of B. Therefore, C has 3(2X) = 6X books.

Therefore, the total number of books with A, B and C combined is X+2X+6X = 9X.

Only one of the given options is divisible by 9.

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Joined: 10 Jun 2016
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Location: India
Concentration: Operations, Strategy
GMAT 1: 710 Q49 V37
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Re: Andy has half as many books as Bill, who has one third as many books  [#permalink]

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14 Oct 2017, 08:05
1
akshata19 wrote:
My approach
assume 3 variables
Andy - a
Bill - b
charlie - c

a= 1/2 b -----> i.e b=2a
b= 1/3 c -----> i.e c=3b = 3*2a = 6a

Total = a + b + c
= a + 2a + 6a
=9a

hence the total should be divisible by 9
only option is 90 Hence C

Just have a query what if 2 options are divisible by 9

To answer your query, I suppose if more than one option is divisible by 9, the test-makers might include a condition such as, "the maximum/minimum number of books they could have together"
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Joined: 10 Apr 2017
Posts: 38
Schools: Kelley '20
Re: Andy has half as many books as Bill, who has one third as many books  [#permalink]

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14 Oct 2017, 08:37
Let A has X books. Therefore, B has 2X books, since number of books with A is half that of B.

In the same vein, number of books with C is thrice that of B. Therefore, C has 3(2X) = 6X books.

Therefore, the total number of books with A, B and C combined is X+2X+6X = 9X.

Only one of the given options is divisible by 9.

Re: Andy has half as many books as Bill, who has one third as many books &nbs [#permalink] 14 Oct 2017, 08:37
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