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21 Dec 2011, 06:50
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B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
95%
(hard)
Question Stats:
41% (03:13) correct
59%
(02:44)
wrong
based on 123
sessions
History
Date
Time
Result
Not Attempted Yet
Andy starts his journey from A to B and Ben starts his journey from B to A at the same time.After passing each other they complete their journeys in 3 1/3 and 4 4/5 hours respectively.Find the speed of Ben if Andy traveled at 12 miles/hr.
a) 8.33 m/hr
b) 10 m/hr
c) 22 m/hr
d) 20 m/hr
e)16.66 m/hr
a) 8.33 m/hr
b) 10 m/hr
c) 22 m/hr
d) 20 m/hr
e)16.66 m/hr
OA is different from what I get.
IMO it should be A. Can someone explain how do u get B as the answer and what is wrong with my approach below ?
My soln goes like this ..
hence equating
x*24/5 = 12*10/3
x= 25/3 or 8.33
IMO it should be A. Can someone explain how do u get B as the answer and what is wrong with my approach below ?
My soln goes like this ..
- Person Rate time distance
Andy 12 m/hr 10/3 40 miles(12*10/3)
Ben x 24/5 40 miles ( distance has to be the same since its B to A)
hence equating
x*24/5 = 12*10/3
x= 25/3 or 8.33
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21 Dec 2011, 13:59
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rvinodhini
Your calculations look perfect, but I think they answer a different question from the one the question designer intended. I don't find the wording of this question to be good at all, but I'm pretty sure what they mean is this: from the point in time at which Andy and Ben meet, it takes a *further* 3 1/3 hours for Andy to complete his journey, and a *further* 4 4/5 hours for Ben to complete his journey. So if it takes them t hours to meet, Andy will end up traveling for a total of t + 10/3 hours, and Ben a total of t + 24/5 hours. That's a more difficult problem than the one you solved. I don't have time to write up a solution at the moment, but I can later if that would be helpful.
22 Dec 2011, 04:02
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IanStewart
Thanks Stewart .. I tried solving the way you have mentinoed, but ended up with a complex equation (2-3 unknowns) and.Can you please post an easier way of solving this ...
