Hi All,

We're told that Anna and Carol buy CDs and tapes at a music store that sells each of its CDs for a certain price and each of its tapes for a certain price. Anna spends TWICE as much as Carol spends, buying THREE times as many CDs and the SAME number of tapes. If Carol spends $50.00 on four CDs and five tapes, we're asked for the price of one tape cost. This question can be approached in a couple of different ways; since every approach requires that you translate the information into equations, you might find it easiest to approach this work Algebraically.

Since Carol spent $50 on 4 CDs and 5 tapes, we can create the following equation:

50 = 4C + 5T

We know that Anna spends TWICE as much as Carol, buying 3 times as many CDs and the same number of tapes. This can be translated into:

100 = 12C + 5T

Thus, the difference in the total spent comes down to the difference in the number of CDs purchased:

An extra 50 dollars gets you an extra 8 CDs

50 = 8C

50/8 = C

25/4 = C

We can now 'plug' this value into the first equation:

50 = (4)(25/4) + 5T

50 = 25 + 5T

25 = 5T

5 = T

Final Answer:

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Rich

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# Rich Cohen

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