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19 Mar 2003, 10:14
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Bookmarks
Another interesting one from the Hakob's set:
What is the probability of bearing two boys from four born babies?
A) 1/5
B) 1/8
C) 1/2
D) 3/8
E) 6/11
What is the probability of bearing two boys from four born babies?
A) 1/5
B) 1/8
C) 1/2
D) 3/8
E) 6/11
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19 Mar 2003, 11:07
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commander
isn't it necessary to know how many girls and boys there are in the group of four babies 
not really, you just start out assuming that you can have only boys and girls; not neutrals
Then I think you will need to calculate how many ways you can get 2 boys out of a group of 4, which is C(2,4) = 6
Then probability kicks in....
I am not good in these, but I will try, I got 3/8
or at least I can explain the logic behind it:
dude 
