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joemama142000
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remgeo
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Why not C.

from the question 5 p costs $6

From stat 1 8 p costs $7.5 (not sufficient)

From Stat2 10 p costs $8.5 ( not sufficient)

combining together,

8-5 =3 p costs $ 1.5
10-5 =5 p costs $2.5


there is a direct relation, the additional pound of apple costs $0.5 after the first 5 pound for $6.

so I would pick C.
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remgeo
joemama142000
Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost?
1). Cost on 8 pounds is $1.5 more than that on 5 pounds.
2). Cost on 10 pounds is $1 more than that on 8 pounds.

$6 = nx + (5-n)y
where n is basic no of lbs
x is amount for n no of lbs
(5-n) is remaining lbs
y is charge for remaining lbs.

Using 1) $7.5 = nx + (8-n)y
We can solve for y but not the remaining.
Using 2) we cannot solve for n,x etc
Using both, again not possible.

Hence E.


Your objective is to find y and that you can.
then just add 10y to the cost of 5 lb - to answer the question
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Goreg
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I would go with C too.

Choosing A means that you take it as standard that the basic amount is 5 pounds and the basic price is 6$, which is not given by the stem.

The progression becomes obvious only after combining the two statements.

Goreg
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old_dream_1976
remgeo
joemama142000
Apples' price consist a basic cost for a basic amount plus an additional cost for each pound thereafter. If 5 pounds apple cost $6, how much did 15 pounds cost?
1). Cost on 8 pounds is $1.5 more than that on 5 pounds.
2). Cost on 10 pounds is $1 more than that on 8 pounds.

$6 = nx + (5-n)y
where n is basic no of lbs
x is amount for n no of lbs
(5-n) is remaining lbs
y is charge for remaining lbs.

Using 1) $7.5 = nx + (8-n)y
We can solve for y but not the remaining.
Using 2) we cannot solve for n,x etc
Using both, again not possible.

Hence E.

Your objective is to find y and that you can.
then just add 10y to the cost of 5 lb - to answer the question


But the question says price consists a basic cost for a basic amount. But we dont know what that basic amount is. How can you assume that it is 5?
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15 pounds cost = C = nx + (15-x)m ---(1)
n = basic cost
m = cost per pound thereafter
x = basic amount


We also know,

6 = nx + (5-x)m
So nx = 6 - (5-x)m

Subsitute this to (1), we have:

C = 6 - (5-x)m + (15-x)m = 6 - 5m + xm + 15m -xm = 6 - 10m

So we just need to solve for m.

From 1) we can solve for n as we can write the simultaneous equations:

6 = nx + (5-x)m -- (1)
7.5 = nx + (8-x)m -- (2)

Just take (2) - (1) and solve for m.

(1) is sufficient.

From 2) Cost of 10 pounds apples is 1 dollar more than cost on 8 pounds apple.

We only know

Cost on 8 pounds apple, A = nx + (8-x)m
Cost on 10 pounds apple, A+1 = nx + (10-x)m

Subtracting,

1 = 10m-xm-8m+xm = 2m
m = 1/2

Sufficient.

I go with D.



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