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Arithmetic4

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Manager
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Joined: 19 Aug 2009
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Kudos [?]: 284 [0], given: 46

Arithmetic4 [#permalink]

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New post 07 Nov 2009, 02:06
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A
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The total salary of A,B ,C is $444. If they spend 80%,85% and 75% of their salaries respectively, their savings are 7:6:9. Then salary of B is

1. 140
2. 160
3. 144

Kudos [?]: 284 [0], given: 46

Senior Manager
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Joined: 18 Aug 2009
Posts: 299

Kudos [?]: 364 [0], given: 9

Re: Arithmetic4 [#permalink]

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New post 07 Nov 2009, 03:19
B. 160 ?

Went by brute force (5+mins), must be some better way to do it...

B=444 - (A+C)

A's saving = 20% = (1/5)A
B's saving = (3/20)B
C's saving = (1/4)C

Using the given ration to get A & C in B form:
[(1/5)A]/[(3/20)B]=7/6 => A=(7/8)B
Similarly C=(9/10)B

So B= 444 - [(7/8)B + (9/10)B]
Solving this equation; B=160

Kudos [?]: 364 [0], given: 9

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Affiliations: CA - India
Joined: 27 Oct 2009
Posts: 45

Kudos [?]: 790 [1], given: 5

Location: India
Schools: ISB - Hyderabad, NSU - Singapore
Re: Arithmetic4 [#permalink]

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New post 07 Nov 2009, 07:04
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Spendings of A, B and C are 80%, 85% and 75%. so we can derive that total spending to be 80% of the total.

Total salary is 444, which means total spending (80%) is approx. $ 355.2 and savings is $ 88.8. B's share in it is 6/22 or approx. $ 24 which 15% of his earning. Hence B's salary should be $ 160.

Is this right OA?

Kudos [?]: 790 [1], given: 5

Manager
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Posts: 227

Kudos [?]: 301 [0], given: 25

Re: Arithmetic4 [#permalink]

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New post 10 Nov 2009, 00:30
Good one Kalpesh

Nice way

Agree with 160$

Kudos [?]: 301 [0], given: 25

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Re: Arithmetic4 [#permalink]

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New post 11 Nov 2009, 21:32
kalpeshchopada7 wrote:
Spendings of A, B and C are 80%, 85% and 75%. so we can derive that total spending to be 80% of the total.

Total salary is 444, which means total spending (80%) is approx. $ 355.2 and savings is $ 88.8. B's share in it is 6/22 or approx. $ 24 which 15% of his earning. Hence B's salary should be $ 160.

Is this right OA?


I also used approximation but of a different kind. I assumed 15% of B's salary= Multiple of 6 in order to get integer values for savings of A&B&C. Got to option "160" and worked backwards to verify if all the salaries added up to 444

Kudos [?]: 14 [0], given: 9

Manager
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Kudos [?]: 82 [0], given: 10

Re: Arithmetic4 [#permalink]

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New post 12 Nov 2009, 03:06
kalpeshchopada7 wrote:
Spendings of A, B and C are 80%, 85% and 75%. so we can derive that total spending to be 80% of the total.

Total salary is 444, which means total spending (80%) is approx. $ 355.2 and savings is $ 88.8. B's share in it is 6/22 or approx. $ 24 which 15% of his earning. Hence B's salary should be $ 160.

Is this right OA?



Hi kalpeshchopada7,

I guess that you are taking in this example the assumption that all salaries are almost the same...
Let's imagine salary A = 10$ and salary C = 10$ ... you will have some troubles to find the good solution.

Even if this way is really smart, the assumption could kill you.

Kudos [?]: 82 [0], given: 10

Re: Arithmetic4   [#permalink] 12 Nov 2009, 03:06
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