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18 Nov 2022, 04:55
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E
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
66% (01:40) correct
34%
(01:13)
wrong
based on 67
sessions
History
Date
Time
Result
Not Attempted Yet
18 Nov 2022, 07:09
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Question
x(y+z) > 0
Inference: This statement holds true in the below conditions.
1) x > 0 & y > -z
2) x < 0 & y < -z
So to answer this question we need to know the positive negative nature of x and the relative position of y and -z with respect to each other.
Statement 1
xyz > 0
We know the product of xyz is greater than 0, however we do not have any information on either the sign of x or the relative position of y and -z.
Hence, we can eliminate the statement A and D.
Statement 2
yz > 0
We know the product of yz is greater than 0, can't say if y > -z or vice versa. Also, there is no information on the sign of x. Hence we can eliminate B.
Combined
The statements combined tell us that x > 0, however the relative position of y and -z is still not known.
Option E
x(y+z) > 0
Inference: This statement holds true in the below conditions.
1) x > 0 & y > -z
2) x < 0 & y < -z
So to answer this question we need to know the positive negative nature of x and the relative position of y and -z with respect to each other.
Statement 1
xyz > 0
We know the product of xyz is greater than 0, however we do not have any information on either the sign of x or the relative position of y and -z.
Hence, we can eliminate the statement A and D.
Statement 2
yz > 0
We know the product of yz is greater than 0, can't say if y > -z or vice versa. Also, there is no information on the sign of x. Hence we can eliminate B.
Combined
The statements combined tell us that x > 0, however the relative position of y and -z is still not known.
Option E
15 Dec 2023, 04:26
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A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
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