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=>

Since \(AC:CD:DB = 1:2:3\), we can put \(AC = k, CD = 2k\) and \(DB = 3k\).

Then \(k + 2k + 3k = 6k = 4 – (-5) = 9\) and \(k = \frac{3}{2}.\)

Thus, \(C = A + k = -5 + (\frac{3}{2}) = -(\frac{7}{2}) = -3.5\) and \(D = B – 3k = 4 – \frac{9}{2} = -(\frac{1}{2}) = -0.5.\)

Therefore, B is the answer.
Answer: B
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