Re: As y increases from y = 247 to y = 248, which of the following
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12 Jun 2024, 04:12
I. \(2y−100\)
As y increases from y = 247 to y = 248, \(2y\) becomes bigger while the amount being subtract stays the same, therefore the value of this equation will increase. X
II. \(\frac{50}{y}+80\)
As we are dealing with fractions where the numerator is remains constant in both instances, while the denominator in both exceeds the value of the numerator, then the larger value of the two will be the one with the smaller numerator. Thus, as y increases from y = 247 to y = 248, \(\frac{50}{y}\) becomes smaller.✔
III. \(100−\frac{10}{y^2−3y}\)
Taking out y as a common factor in the bottom: \(100−\frac{10}{y(y−3)}\).
As y increases from y = 247 to y = 248, \(\frac{10}{y(y−3)}\) becomes a smaller value as the denominator value exceeds the value of the numerator in both instances, in which case the value of the fraction with the larger denominator becomes the smaller value. As in both instances the respective fractions are being subtracted from 100, then as the value of y increases the smaller \(\frac{10}{y(y−3)}\) becomes which increases the value of \(100−\frac{10}{y(y−3)}\). X
Only II. increases, therefore
ANSWER B