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At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin

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At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin  [#permalink]

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New post 11 Mar 2018, 21:02
00:00
A
B
C
D
E

Difficulty:

  15% (low)

Question Stats:

93% (01:01) correct 7% (00:50) wrong based on 54 sessions

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Re: At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin  [#permalink]

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New post 12 Mar 2018, 00:18
Bunuel wrote:
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00

total cookies bought = 30

cc cookie = 2 i.e 2x18 = 36$
om cookie = 1 1x12 = 12

total = 48

avg = 48/30 = 1.6
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At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin  [#permalink]

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New post 12 Mar 2018, 00:40
Bunuel wrote:
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00


Since the proportion of chocolate chip cookies to oatmeal raisin cookies is 3:2,
we can calculate the average price for a cookie to be \(\frac{3*2 + 2*1.5}{5} = \frac{5 + 3}{5} = $1.6\)(Option D)

P.S This concept of bringing down the numbers to proportions can be really useful
when the numbers are bigger!
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Re: At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin  [#permalink]

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New post 12 Mar 2018, 11:38
1
Bunuel wrote:
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00


\(\frac{2*18 + 1*12}{18 + 12}\)

= \(1.60\), Answer will be (D)
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Re: At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin  [#permalink]

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New post 12 Mar 2018, 12:53
pushpitkc wrote:
Bunuel wrote:
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00


Since the proportion of chocolate chip cookies to oatmeal raisin cookies is 3:2,
we can calculate the average price for a cookie to be \(\frac{3*2 + 2*1.5}{5} = \frac{5 + 3}{5} = $1.6\)(Option D)

P.S This concept of bringing down the numbers to proportions can be really useful
when the numbers are bigger!


take the weighted average of the two prices to find the average price of cookie!

Nice solution. +1 Kudos to you sir.
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Re: At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin  [#permalink]

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New post 13 Mar 2018, 17:03
Bunuel wrote:
At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin cookies sell for $1.00. If Paul buys 18 chocolate chip cookies and 12 oatmeal raisin cookies, what is the average price he pays per cookie?

A. $1.20
B. $1.40
C. $1.50
D. $1.60
E. $2.00


We can create the following equation:

[2(18) + 12]/30 = 48/30 = 8/5 = 1.60

Answer: D
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Re: At a bakery, chocolate chip cookies sell for $2.00 and oatmeal raisin   [#permalink] 13 Mar 2018, 17:03
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