anon1 wrote:

At a certain committee meeting only associate professors and assistant professors are present. Each associate professor has brought 2 pencils and 1 chart to the meeting, while each assistant professor has brought 1 pencil and 2 charts. If a total of 10 pencils and 11 charts have been brought to the meeting, how many people are present?

6

7

8

9

10

The solution suggests a formula, but I believe there is an easier way of doing this using something like a chart? I did it once before but I can't remember how to do it, can anyone shine a light in here?

Say there are 'A' associate professors. So we have 2A pencils and A charts.

Say there are 'B' assistant professors. So we have B pencils and 2B charts.

Total pencils are 10 so 2A + B = 10

Total charts are 11 so A + 2B = 11

Add both: 3A + 3B = 21 so A + B = 7

Total number of people = 7

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Karishma

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