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At a certain factory, the average (arithmetic mean) wage of 20 of the

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At a certain factory, the average (arithmetic mean) wage of 20 of the  [#permalink]

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New post 25 Sep 2018, 04:55
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Question Stats:

100% (01:44) correct 0% (00:00) wrong based on 7 sessions

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At a certain factory, the average (arithmetic mean) wage of 20 of the workers is $25,000, the average wage of 25 other workers is $20,000, and the average wage of the remaining 5 workers is $100,000. What is the average wage of the 50 workers at the company?

(A) $25,000
(B) $30,000
(C) $35,000
(D) $50,000
(E) $75,000

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At a certain factory, the average (arithmetic mean) wage of 20 of the  [#permalink]

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New post 27 Sep 2018, 07:16
\(\frac{x}{20}\)=\(25\)
-->\(x=500\)

\(\frac{y}{25}\)=\(20\)
-->\(y=500\)

\(\frac{z}{5}\)=\(100\)
-->\(z=500\)

\(\frac{x+y+z}{50}\) --> \(\frac{1500}{50}\) --> \(30\)

Hence, B.
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At a certain factory, the average (arithmetic mean) wage of 20 of the   [#permalink] 27 Sep 2018, 07:16
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