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At a certain fitness center, are more than 1/6 of the members over 30

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At a certain fitness center, are more than 1/6 of the members over 30 [#permalink]

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At a certain fitness center, are more than 1/6 of the members over 30 years of age?

(1) Exactly 60 percent of male members are over 20 years of age, and of these, 3⁄5 are over 30 years of age.

(1) Exactly 15 female members are over 30 years of age.
[Reveal] Spoiler: OA

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Last edited by Bunuel on 27 Nov 2017, 00:32, edited 1 time in total.
Renamed the topic, edited the question and edited the tags.

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Re: At a certain fitness center, are more than 1/6 of the members over 30 [#permalink]

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New post 27 Nov 2017, 05:35
Sasindran wrote:
At a certain fitness center, are more than 1/6 of the members over 30 years of age?

(1) Exactly 60 percent of male members are over 20 years of age, and of these, 3⁄5 are over 30 years of age.

(1) Exactly 15 female members are over 30 years of age.


Statement 1: let there me \(x\) males. so number of males over \(20=60\)%\(*x=0.6x\)

number of males over 30 \(= \frac{3}{5}*0.6x=0.36x\)

but nothing mentioned about female. So insufficient

Statement 2: let there me \(y\) females. out of \(y\), \(15\) are over 30. but nothing mentioned about male. Insufficient

Combining 1 & 2 total member \(= x+y\)

total member over 30 \(=0.36x+15\)

Hence the ratio of member over 30 \(=\frac{(0.36x+15)}{x+y}\). so we have two unknown variables. Insufficient

Option E

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Re: At a certain fitness center, are more than 1/6 of the members over 30 [#permalink]

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New post 05 Dec 2017, 10:16
Sasindran wrote:
At a certain fitness center, are more than 1/6 of the members over 30 years of age?

(1) Exactly 60 percent of male members are over 20 years of age, and of these, 3⁄5 are over 30 years of age.

(1) Exactly 15 female members are over 30 years of age.



why is A not the answer? when we know that 1/6 = .16

and if we take 1 as total number of members in gym

So, 60 percent male above 20 age = .60

and 3/5 of .60 = .36

so 0.36>0.16

which means THERE ARE MORE THAN 1/6 people in the gym who are 30 year old or above...ONLY MALE CAN PROVIDE ENOUGH INFO


Please let me know where I am wrong

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Re: At a certain fitness center, are more than 1/6 of the members over 30 [#permalink]

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New post 05 Dec 2017, 10:40
rocko911 wrote:
Sasindran wrote:
At a certain fitness center, are more than 1/6 of the members over 30 years of age?

(1) Exactly 60 percent of male members are over 20 years of age, and of these, 3⁄5 are over 30 years of age.

(1) Exactly 15 female members are over 30 years of age.



why is A not the answer? when we know that 1/6 = .16

and if we take 1 as total number of members in gym

So, 60 percent male above 20 age = .60

and 3/5 of .60 = .36

so 0.36>0.16

which means THERE ARE MORE THAN 1/6 people in the gym who are 30 year old or above...ONLY MALE CAN PROVIDE ENOUGH INFO


Please let me know where I am wrong


Hi rocko911

The highlighted portion is wrong. As you have assumed total member to be 1, so you cannot again assume that total male member is also 1.

60%of male => 0.6*something less than 1 (male+female=1)
so you will have to assume some other variable for male/female

Kudos [?]: 306 [0], given: 39

Re: At a certain fitness center, are more than 1/6 of the members over 30   [#permalink] 05 Dec 2017, 10:40
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