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At a certain soccer club, the number of players increased by 10 percen

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At a certain soccer club, the number of players increased by 10 percen  [#permalink]

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New post Updated on: 04 Dec 2017, 02:29
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Question Stats:

59% (02:07) correct 41% (01:42) wrong based on 32 sessions

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At a certain soccer club, the number of players increased by 10 percent between 2015 and 2016. If the number of male players decreased by 5 percent and the number of female players increased by 15 percent, what is the ratio of female players to male players in 2015?
A) 1:3
B) 1:2
C) 3:2
D) 2:1
E) 3:1

OPEN DISCUSSION OF THIS QUESTION IS HERE: at-a-certain-soccer-club-the-number-of-players-increased-by-10-percen-238615.html

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Originally posted by helloSimba on 20 Apr 2017, 11:46.
Last edited by Bunuel on 04 Dec 2017, 02:29, edited 3 times in total.
Edited the question.
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Re: At a certain soccer club, the number of players increased by 10 percen  [#permalink]

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New post 20 Apr 2017, 11:54
let no. male players be x and female players be y
as per the question stem : x*95/100+y*115/100 = (x+y)*110/100 => y/x =3/1 -> option E
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Re: At a certain soccer club, the number of players increased by 10 percen  [#permalink]

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New post 20 Apr 2017, 12:28
attari92 wrote:
let no. male players be x and female players be y
as per the question stem : x*95/100+y*115/100 = (x+y)*110/100 => y/x =3/1 -> option E


Isnt this the ratio of 2015 not 2016? :?
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Re: At a certain soccer club, the number of players increased by 10 percen  [#permalink]

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New post 20 Apr 2017, 21:43
Fazil Nadeem Hussain wrote:
attari92 wrote:
let no. male players be x and female players be y
as per the question stem : x*95/100+y*115/100 = (x+y)*110/100 => y/x =3/1 -> option E


Isnt this the ratio of 2015 not 2016? :?



Even the increase no. would drift with the same ratio cause we are considering an overall increase in the same exact proportion. We can't ascertain a ratio with the conditional part of a question stem and it was mentioned only to manipulate it further. Assume total to be 100; let x and y part be 30 and 70. Now, an overall increase of 10% will also let x and y part to go up by 3 and 7 respectively and not to mention that the ratio doesn't change.
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Re: At a certain soccer club, the number of players increased by 10 percen  [#permalink]

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New post 04 Dec 2017, 02:28
helloSimba wrote:
At a certain soccer club, the number of players increased by 10 percent between 2015 and 2016. If the number of male players decreased by 5 percent and the number of female players increased by 15 percent, what is the ratio of female players to male players in 2015?
A) 1:3
B) 1:2
C) 3:2
D) 2:1
E) 3:1


Edited the question. It asks about the ration in 2015.

Veritas Prep Official Solution:



We can solve this one with the weighted average mapping strategy or with algebra. For the mapping strategy:

-5%...............10%......15%

M..........15...........5......F

This gives us a female:male ratio of 15:5, or 3:1.

To solve algebraically, we can set up the following equation:
\(1.1(f+m)=1.15f+.95m\). By manipulating, we can get to \(0.15m =0.05f\), or \(\frac{f}{m}=\frac{0.15}{0.05}=\frac{3}{1}\).

Answer: E.

OPEN DISCUSSION OF THIS QUESTION IS HERE: at-a-certain-soccer-club-the-number-of-players-increased-by-10-percen-238615.html

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This discussion does not meet community quality standards. It has been retired.


If you would like to discuss this question please re-post it in the respective forum. Thank you!

To review the GMAT Club's Forums Posting Guidelines, please follow these links: Quantitative | Verbal Please note - we may remove posts that do not follow our posting guidelines. Thank you.

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Re: At a certain soccer club, the number of players increased by 10 percen &nbs [#permalink] 04 Dec 2017, 02:28
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