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15 Apr 2018, 09:42
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A
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
65%
(hard)
Question Stats:
62% (02:02) correct
38%
(02:12)
wrong
based on 334
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At a local coffee shop, pastries may have nuts, chocolate, both, or neither. If 400 pastries were sold Friday, and if of those, 60% contained chocolate how many of those sold contained only nuts?
(1) The number of pastries containing neither is one-fourth of the number containing chocolate.
(2) One third of pastries sold containing chocolate also contained nuts.
(1) The number of pastries containing neither is one-fourth of the number containing chocolate.
(2) One third of pastries sold containing chocolate also contained nuts.
Updated on: 15 Apr 2018, 11:27
Originally posted by DavidTutorexamPAL on 15 Apr 2018, 10:20.
Last edited by DavidTutorexamPAL on 15 Apr 2018, 11:27, edited 1 time in total.
Last edited by DavidTutorexamPAL on 15 Apr 2018, 11:27, edited 1 time in total.
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Bunuel
At a local coffee shop, pastries may have nuts, chocolate, both, or neither. If 400 pastries were sold Friday, and if of those, 60% contained chocolate how many of those sold contained only nuts?
(1) The number of pastries containing neither is one-fourth of the number containing chocolate.
(2) One third of pastries sold containing chocolate also contained nuts.
(1) The number of pastries containing neither is one-fourth of the number containing chocolate.
(2) One third of pastries sold containing chocolate also contained nuts.
Items belonging to 2 overlapping sets can be in 4 distinct parts: the overlap between the sets, in only one set, in only the other set, or in neither set.
To calculate the part that is only nuts we need to know the other 3 (overlap, only chocolate, neither).
We'll look for a statement that gives us this information, a Logical approach.
Note that we're told the total amount of chocolate, that is the 'overlap' + 'only chocolate'. So all we need to know is the 'neither' part.
(1) this gives us the 'neither' part - enough!
Sufficient.
(2) this gives us the 'overlap' part - not enough.
Insufficient.
(A) is our answer.
15 Apr 2018, 11:20
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Bunuel
At a local coffee shop, pastries may have nuts, chocolate, both, or neither. If 400 pastries were sold Friday, and if of those, 60% contained chocolate how many of those sold contained only nuts?
(1) The number of pastries containing neither is one-fourth of the number containing chocolate.
(2) One third of pastries sold containing chocolate also contained nuts.
(1) The number of pastries containing neither is one-fourth of the number containing chocolate.
(2) One third of pastries sold containing chocolate also contained nuts.
So basically there are four kinds of pastries: (1) having Only Chocolate, (2) having both Chocolate/Nuts, (3) having Only Nuts, (4) having Neither. We have to determine the number of type (3) pastries, i.e., having Only Nuts. And we know that (1) + (2) + (3) + (4) = 400
We are given that out of 400, 60% or 0.6*400 = 240 contain chocolates. So these 240 are sum of type (1) and (2). So we just need to know (4) to calculate the value of (3).
Statement 1 - gives us the number of type (4) pastries. these are 1/4 * 240 = 60. So we can find type (3). Sufficient.
Statement 2 - tells us that type (2) are 1/3 of type (1). But this is not sufficient to calculate type (3).
Hence A answer
