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Bunuel
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At a local election there were two propositions on the ballot, R and S 27 Nov 2018, 00:26
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35% (medium)

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76% (02:45) correct 24% (03:01) wrong based on 151 sessions

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At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the number who voted "yes" for R but "no" for S was 750 and the number who voted "yes" for S but "no" for R was 310, how many voted "yes" for both propositions?

A. 122
B. 127
C. 130
D. 135
E. 140
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C
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At a local election there were two propositions on the ballot, R and S 27 Nov 2018, 10:11
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Bunuel
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the number who voted "yes" for R but "no" for S was 750 and the number who voted "yes" for S but "no" for R was 310, how many voted "yes" for both propositions?

A. 122
B. 127
C. 130
D. 135
E. 140
Show more

Since given that yes of R = 2* yes of S

So 310 Yes of S = 310* 2= 620 Yes of R
And for both 750-620 = 130 option C
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At a local election there were two propositions on the ballot, R and S 09 Dec 2018, 09:03
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Hi Archit3110
750 is given only for Yes to R and No to S , not both R and S
you are including both R and S in 750


Archit3110
Bunuel
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the number who voted "yes" for R but "no" for S was 750 and the number who voted "yes" for S but "no" for R was 310, how many voted "yes" for both propositions?

A. 122
B. 127
C. 130
D. 135
E. 140

Since given that yes of R = 2* yes of S

So 310 Yes of S = 310* 2= 620 Yes of R
And for both 750-620 = 130 option C
Show more
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At a local election there were two propositions on the ballot, R and S 09 Dec 2018, 09:39
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sunita123
Hi Archit3110
750 is given only for Yes to R and No to S , not both R and S
you are including both R and S in 750


Archit3110
Bunuel
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the number who voted "yes" for R but "no" for S was 750 and the number who voted "yes" for S but "no" for R was 310, how many voted "yes" for both propositions?

A. 122
B. 127
C. 130
D. 135
E. 140

Since given that yes of R = 2* yes of S

So 310 Yes of S = 310* 2= 620 Yes of R
And for both 750-620 = 130 option C
Show more

sunita123 solution attached 2x2 matrix..

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File comment: 2x2 matrix
IMG_20181209_220720860.jpg
IMG_20181209_220720860.jpg [ 3.54 MiB | Viewed 10736 times ]

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At a local election there were two propositions on the ballot, R and S 09 Dec 2018, 09:41
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sunita123
Hi Archit3110
750 is given only for Yes to R and No to S , not both R and S
you are including both R and S in 750


Archit3110
Bunuel
At a local election there were two propositions on the ballot, R and S. Twice as many voters voted "yes" for R as for S. If the number who voted "yes" for R but "no" for S was 750 and the number who voted "yes" for S but "no" for R was 310, how many voted "yes" for both propositions?

A. 122
B. 127
C. 130
D. 135
E. 140

Since given that yes of R = 2* yes of S

So 310 Yes of S = 310* 2= 620 Yes of R
And for both 750-620 = 130 option C
Show more

sunita123 : i had actually solved question linearly , anyways I have attached the 2x2 matrix solution hope this helps .
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At a local election there were two propositions on the ballot, R and S 11 Dec 2018, 02:27
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Bunuel could you solve this? I think there's a problem with the question
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Nikhilgaur29
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At a local election there were two propositions on the ballot, R and S 14 Dec 2019, 07:29
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R S
I. Y1 Y1 = we have to find out ??
II. N2 N2
IIII. Y3 N3. = 750 given
IV. N4 Y4. = 310 given

As per question

2(Y1+Y4)=(Y1+Y3)
2(Y1+310)=(Y1+750)

Y1 = 130
This implies 130 people voted yes for both R&S

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At a local election there were two propositions on the ballot, R and S 29 Aug 2024, 16:00
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