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08 Apr 2016, 02:46
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D
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
45%
(medium)
Question Stats:
73% (02:51) correct
27%
(02:50)
wrong
based on 325
sessions
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Not Attempted Yet
At a particular pizza shop, a pizza can be created from any combination of 3 different types of spice, 7 different types of meat, among which are pepperoni and anchovies, and 4 different types of cheese. If a customer at the shop decides to order a pizza with 1 type of spice, 2 types of cheese, and 4 types of meat but without pepperoni and anchovies together, how many possible ways to garnish the pizza are available to the customer?
A. 6
B. 35
C. 120
D. 450
E. 740
A. 6
B. 35
C. 120
D. 450
E. 740
08 Apr 2016, 21:41
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Number of possible ways to select 1 type of spice = 3c1 = 3
Number of possible ways to select 2 types of cheese = 4c2 = 6
(Here we can pick our answer as D- 450 since it is the only answer that is divisible by 3*6= 18 , but most likely on the GMAT there will be more another answer that will be divisible by 18 )
Number of possible ways to select 4 types of meat but without pepperoni and anchovies together
= Total number of ways without any restriction - Total number of ways in which pepperoni and anchovies together
= 7c4 - 5c2
=35 - 10
=25
Possible ways to garnish the pizza are available to the customer = 3*6 * 25
=450
Answer D
Number of possible ways to select 2 types of cheese = 4c2 = 6
(Here we can pick our answer as D- 450 since it is the only answer that is divisible by 3*6= 18 , but most likely on the GMAT there will be more another answer that will be divisible by 18 )
Number of possible ways to select 4 types of meat but without pepperoni and anchovies together
= Total number of ways without any restriction - Total number of ways in which pepperoni and anchovies together
= 7c4 - 5c2
=35 - 10
=25
Possible ways to garnish the pizza are available to the customer = 3*6 * 25
=450
Answer D
19 Sep 2018, 09:07
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AnkitOrYadav
You need to select 4 meat out of 7. So if you consider pepperoni and anchovies together , 2 out 4 slot is filled. Remaining 2 slot can filled with remaining 5 options.
Therefore , 5c2
