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27 Sep 2005, 21:06
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At Joe’s Pizzeria, a small pie measures 12 inches in diameter. A large pie measures 16 inches in diameter. Customers ordering the large pie pay 10% less per amount of pie received. If the small pie costs $6.30, what does the large pie cost?
(A) $7.56
(B) $8.40
(C) $10.08
(D) $11.20
(E) $11.76
(A) $7.56
(B) $8.40
(C) $10.08
(D) $11.20
(E) $11.76
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27 Sep 2005, 21:23
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I got C) $10.08
12 Dia pizza costs $6.30
16 Dia pizza costs ? Say x
(pi)Sqr(12/2) / (0.90)(pi) Sqr(16/2) = 6.30/x
(we need 0.90 to take into account - large pie 10% less per amount or 10% less per area)
This works out to x = 10.08
12 Dia pizza costs $6.30
16 Dia pizza costs ? Say x
(pi)Sqr(12/2) / (0.90)(pi) Sqr(16/2) = 6.30/x
(we need 0.90 to take into account - large pie 10% less per amount or 10% less per area)
This works out to x = 10.08
27 Sep 2005, 22:53
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Got 10.08$ too
small one is 6.3
we need to find the price for the big pizza, we know that it will be 10% less than the amount of pizza so first let's find the amount we will get, then we will know the normal price and therefore the final price (with reduction) :
small pizza : piR^2=pi6^2=36pi
big pizza : 64pi
64/36= 16/9
so the price will be 16/9*6.3 -> 16/9*63/10 -> 16*7/10 -> 8*7/5 = 56/5
do a fast division and you'll find that 56/5 = 11.2
10% of 11.2 = 1.12
final price will be 11.2-1.12 = 10.08
small one is 6.3
we need to find the price for the big pizza, we know that it will be 10% less than the amount of pizza so first let's find the amount we will get, then we will know the normal price and therefore the final price (with reduction) :
small pizza : piR^2=pi6^2=36pi
big pizza : 64pi
64/36= 16/9
so the price will be 16/9*6.3 -> 16/9*63/10 -> 16*7/10 -> 8*7/5 = 56/5
do a fast division and you'll find that 56/5 = 11.2
10% of 11.2 = 1.12
final price will be 11.2-1.12 = 10.08
