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28 Jul 2016, 16:00
Kudos
Bookmarks
B
Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
Difficulty:
75%
(hard)
Question Stats:
57% (02:43) correct
43%
(02:34)
wrong
based on 108
sessions
History
Date
Time
Result
Not Attempted Yet
At the first meeting of the amputees’ support group, there were
93 fewer handshakes than there would have been if everyone
had at least one arm and shook hands once with everyone else.
The people with less than one arm made up 1/11 of the group.
How many of them were there?
A. 2
B. 3
C. 4
D. 5
E. 6
Source: me
93 fewer handshakes than there would have been if everyone
had at least one arm and shook hands once with everyone else.
The people with less than one arm made up 1/11 of the group.
How many of them were there?
A. 2
B. 3
C. 4
D. 5
E. 6
Source: me
29 Jul 2016, 00:46
Kudos
Bookmarks
--> If we assume there are 2 people with less than one arm:
ie 2 people out of total 22.
So total handshakes by these two people= [2*20 + (2*1)/2]=[40+1]=41 >>> Not correct we need 93 handshakes
--->If we assume, there are 3 people:
ie 3 out of total 33.
So handshakes by these 3 persons= [3*30 + (3*2)/2]= [90+3]= 93 >>> Correct answer B
ie 2 people out of total 22.
So total handshakes by these two people= [2*20 + (2*1)/2]=[40+1]=41 >>> Not correct we need 93 handshakes
--->If we assume, there are 3 people:
ie 3 out of total 33.
So handshakes by these 3 persons= [3*30 + (3*2)/2]= [90+3]= 93 >>> Correct answer B
