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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,

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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, [#permalink]

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New post 28 Jul 2017, 08:47
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Question Stats:

100% (00:16) correct 0% (00:00) wrong based on 98 sessions

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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, [#permalink]

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New post 28 Jul 2017, 10:53
Bunuel wrote:
Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs


Distance : 350 miles
Speed(Average) - 50 mph

Time taken = Distance/Speed

The total time taken is \(\frac{350}{50} = 7\)(Option C)
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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, [#permalink]

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New post 06 Aug 2017, 10:09
Time = Distance/Speed

Time taken = 350/50 = 7 hours

Answer C
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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, [#permalink]

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New post 29 Mar 2018, 17:38
Bunuel wrote:
Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs


We can use the formula:

Average = total distance/total time

50 = 350/t

50t = 350

t = 7 hours

Answer: C
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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, [#permalink]

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New post 14 Apr 2018, 23:11
Bunuel wrote:
Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs


Time = Distance / Speed

Time = 350/50

Time = 7 hours

(C)
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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,   [#permalink] 14 Apr 2018, 23:11
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