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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,

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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,  [#permalink]

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28 Jul 2017, 07:47
00:00

Difficulty:

5% (low)

Question Stats:

99% (00:24) correct 1% (00:11) wrong based on 117 sessions

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Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,  [#permalink]

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28 Jul 2017, 09:53
Bunuel wrote:
Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

Distance : 350 miles
Speed(Average) - 50 mph

Time taken = Distance/Speed

The total time taken is $$\frac{350}{50} = 7$$(Option C)
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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,  [#permalink]

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06 Aug 2017, 09:09
Time = Distance/Speed

Time taken = 350/50 = 7 hours

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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,  [#permalink]

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29 Mar 2018, 16:38
Bunuel wrote:
Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

We can use the formula:

Average = total distance/total time

50 = 350/t

50t = 350

t = 7 hours

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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles,  [#permalink]

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14 Apr 2018, 22:11
Bunuel wrote:
Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, a distance of 350 miles. How long does it take him to complete the trip?

(A) 4 hrs

(B) 5 hrs

(C) 7 hrs

(D) 10 hrs

(E) 12 hrs

Time = Distance / Speed

Time = 350/50

Time = 7 hours

(C)
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Re: Bob drives at an average rate of 50 mph from Berkeley to Los Angeles, &nbs [#permalink] 14 Apr 2018, 22:11
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