Bunuel
Bob invested $1,000 at 10 percent annual interest, compounded annually, and Joe invested $2,000 at 5 percent annual interest, compounded annually. The total amount of interest earned by Bob's investment in the first 2 years was how much greater than the total amount of interest earned by Joe's investment in the first 2 years?
A. $2
B. $3
C. $4
D. $5
E. $10
Bob starts with $1000. He earns 10% interest in year one. 10% of $1000 is $100, so he has $1100 at the end of year one. He earns 10% interest in year two. 10% of $1100 is $110. He earned $100 interest in year one and $110 interest in year two. Add those together for a total of $210.
Joe starts with $2000. He earns 5% interest in year one. 5% of $2000 is $100, so he has $2100 at the end of year one. He earns 5% interest in year two. 5% of $2100 is $105. He earned $100 interest in year onw and $105 interest in year two. Add those together for a total of $205.
Bob earned $210 and Joe earned $205.
Answer choice D.
Note that we did NOT need to calculate how much either guy had at the end of year two in order to get to the right answer. Pay attention to what you're solving for in order to save unnecessary steps!!