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Boone is making a playlist of 5 songs, but only 2 are suitable to be l

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Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post 27 Feb 2019, 04:47
00:00
A
B
C
D
E

Difficulty:

  35% (medium)

Question Stats:

61% (01:27) correct 39% (01:43) wrong based on 23 sessions

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Re: Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post 27 Feb 2019, 05:08
Last place can be selected in 2 ways.
now the other 4 can be selected in 4! ways.
Total possible ways = 4!*2=48
Ans B
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Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post Updated on: 27 Feb 2019, 09:34
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Bunuel wrote:
Boone is making a playlist of 5 songs, but only 2 are suitable to be last. How many different playlists could Boone make?

A. 24
B. 48
C. 60
D. 120
E. 3,125


total songs a,b,c,d,e
let d,e be last song so our songs a,b,c,x ; x; d&e
so no ways we can make a playlist 4! ways ; 24
and last two songs can be arranged in 2 ways so 24*2;48
IMO B
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Originally posted by Archit3110 on 27 Feb 2019, 05:28.
Last edited by Archit3110 on 27 Feb 2019, 09:34, edited 1 time in total.
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Re: Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post 27 Feb 2019, 05:29
u1983 wrote:
Last place can be selected in 2 ways.
now the other 4 can be selected in 4! ways.
Total possible ways = 4!*2=48
Ans B


u1983
wanted to understand why you have multiplied by 2 ; the question has specified that 2 songs have to be in last so wont we get the sequence in 4! ways?
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Re: Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post 27 Feb 2019, 05:49
u1983 the idea is to choose the last song first so we would have 2 choices and the 1st to 4th songs would have choice 4,3,2,1. Hence the calculation 4!*2

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Re: Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post 27 Feb 2019, 06:53
Archit3110 wrote:
u1983 wrote:
Last place can be selected in 2 ways.
now the other 4 can be selected in 4! ways.
Total possible ways = 4!*2=48
Ans B


u1983
wanted to understand why you have multiplied by 2 ; the question has specified that 2 songs have to be in last so wont we get the sequence in 4! ways?


Hello Archit3110 ..... below is my take.

The Q says : Boone is making a playlist of 5 songs, but only 2 are suitable to be last.

So the last spot can be taken by any of those 2 songs. This implies the last position can be taken up in 2 ways.
Once the last place is defined/selected, we remain with 4 places and 4 songs.
Now those 4 songs can be arranged in 4 places in 4! ways (as order does matter here ).
Hence the total ways = 4!*2=48

Hope this helps!!
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Re: Boone is making a playlist of 5 songs, but only 2 are suitable to be l  [#permalink]

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New post 27 Feb 2019, 06:54
sumi747 wrote:
u1983 the idea is to choose the last song first so we would have 2 choices and the 1st to 4th songs would have choice 4,3,2,1. Hence the calculation 4!*2

Posted from my mobile device


Hello sumi747 ... really could not understand your post ...... was it an explanation or query for me ?? :( :( .....
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Re: Boone is making a playlist of 5 songs, but only 2 are suitable to be l   [#permalink] 27 Feb 2019, 06:54
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