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Box W and Box V each contain several blue sticks and red

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Intern
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Joined: 05 Nov 2008
Posts: 6
Box W and Box V each contain several blue sticks and red [#permalink]

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New post 05 Nov 2008, 20:49
Box W and Box V each contain several blue sticks and red sticks, and all of the red sticks have the same length. The length of each red stick is 18 inches less than the average length of the sticks in Box W and 6 inches greater than the average length of the sticks in Box V. What is the average (arithmetic mean) length, in inches, of the sticks in Box W minus the average length, in inches, of the sticks in Box V?

A. 3
B. 6
C. 12
D. 18
E. 24

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Intern
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Joined: 14 Sep 2003
Posts: 43
Location: california
Re: box w and box v---30 [#permalink]

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New post 05 Nov 2008, 21:11
Say length of Red stick is R

Avg(W) = R + 18

Avg(V) = R - 6

Now subrtracting 1st minus 2nd we get

Avg(W) - Avg(V) = R + 18 - (R - 6) = 24

So my pick E

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Re: box w and box v---30   [#permalink] 05 Nov 2008, 21:11
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Box W and Box V each contain several blue sticks and red

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