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01 May 2026, 10:50
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Be sure to select an answer first to save it in the Error Log before revealing the correct answer (OA)!
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Brian works as a consultant. His only work comes from three companies: Company A, Company B, and Company C. He earns a daily rate of $500 when he works for company A, $600 when he works for company B, and $1000 when he works for company C. If Brian earned a total of $11,300 last month and worked less than five days for Company A, how many days did he work in total?
(1) Brian worked eight days for Company B last month.
(2) Brian worked five days for Company C last month.
The OA will be automatically revealed on Friday 1st of May 2026 10:50:47 PM Pacific Time Zone
(1) Brian worked eight days for Company B last month.
(2) Brian worked five days for Company C last month.
The OA will be automatically revealed on Friday 1st of May 2026 10:50:47 PM Pacific Time Zone
01 May 2026, 19:15
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Let the number of days Brian worked for Companies A, B, and C be a, b, and c.
His total earnings are:
500a + 600b + 1000c = 11,300
We are also given that a < 5.
Statement (1): b = 8
Substitute into the equation:
500a + 600(8) + 1000c = 11,300
500a + 4,800 + 1000c = 11,300
500a + 1000c = 6,500
This simplifies to:
a + 2c = 13
Possible integer solutions with a < 5:
(a, c) = (3, 5) or (1, 6)
Total days worked = a + b + c:
For (3,5): 3 + 8 + 5 = 16
For (1,6): 1 + 8 + 6 = 15
Different totals → statement (1) is not sufficient.
Statement (2): c = 5
Substitute into the equation:
500a + 600b + 5000 = 11,300
500a + 600b = 6,300
Divide by 100:
5a + 6b = 63
Check integer solutions with a < 5:
a = 3 gives b = 8 (valid)
Other values of a < 5 do not give integer b.
So a = 3, b = 8, c = 5.
Total days = 3 + 8 + 5 = 16, uniquely determined → statement (2) is sufficient.
Answer: B
His total earnings are:
500a + 600b + 1000c = 11,300
We are also given that a < 5.
Statement (1): b = 8
Substitute into the equation:
500a + 600(8) + 1000c = 11,300
500a + 4,800 + 1000c = 11,300
500a + 1000c = 6,500
This simplifies to:
a + 2c = 13
Possible integer solutions with a < 5:
(a, c) = (3, 5) or (1, 6)
Total days worked = a + b + c:
For (3,5): 3 + 8 + 5 = 16
For (1,6): 1 + 8 + 6 = 15
Different totals → statement (1) is not sufficient.
Statement (2): c = 5
Substitute into the equation:
500a + 600b + 5000 = 11,300
500a + 600b = 6,300
Divide by 100:
5a + 6b = 63
Check integer solutions with a < 5:
a = 3 gives b = 8 (valid)
Other values of a < 5 do not give integer b.
So a = 3, b = 8, c = 5.
Total days = 3 + 8 + 5 = 16, uniquely determined → statement (2) is sufficient.
Answer: B
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