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Building

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Intern
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Joined: 02 Jun 2009
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Building [#permalink]

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New post 02 Jun 2009, 03:48
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The annual rent collected by a corporation from a certain building was x percent more in 1998 than in 1997 and y percent less in 1999 than in 1998. Was the annual rent collected by the corporation from the building more in 1999 than in 1997?
(1) x > y
(2) 100xy < x – y

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Manager
Manager
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Joined: 08 Feb 2009
Posts: 145

Kudos [?]: 58 [0], given: 3

Schools: Anderson
Re: Building [#permalink]

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New post 11 Jun 2009, 17:33
Answer IMO is B.


(1)
If x = 10%, y = 9.9%, then rent would be 99.11 in 1999 which is LESS than 100.
If x = 10%, y = 1%, then rent would be MORE than 100.

Therefore, INSUFFICIENT.


(2)
Simplifying the expression, we get:
\(100 \hspace{5} < \hspace{5} \frac{1}{y}\hspace{5}-\hspace{5}\frac{1}{x}

\Rightarrow \hspace{5}\) y is a decimal value && x may or may not be a decimal value.

I'm not sure how to proceed to conclude from this point.
But, I think this proves that rent collected was more in 1999 than in 1997, mainly because of the huge difference (100 or more) in values of reciprocals of x and y.


I would like to know the OA.

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Senior Manager
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Joined: 08 Jan 2009
Posts: 326

Kudos [?]: 175 [1], given: 5

Re: Building [#permalink]

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New post 11 Jun 2009, 18:35
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We have discussed it before. The second cond is actually xy/100 < x-y. i would like dtaneja to confirm.

when a amount increases by x% and decrease y % then the total profit % in the transaction is
x -y - xy /100 . Our question is based on this formula.

1. x > y . not sufficient. u still dont xy/100

2. x - y > xy /100.
x - y - xy /100 > 0. so profit.

Sufficent.

hence B

Kudos [?]: 175 [1], given: 5

Re: Building   [#permalink] 11 Jun 2009, 18:35
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