Buster leaves the trailer at noon and walks towards the studio at a co

I agree Bunuel's solution is precise one.
But whenever I stumble upon this question again , i forget the approach how to solve this and it takes me lot of time to figure out .
Especially when trying to solve it algebraically

So here is my visual solution . Hope it helps.


Given: C starts 20 min late than B
To find the relative position

3 possible meeting point i.e X
1. B -------X-------------------------------C

2. B ------------------X--------------------C

3. B -------------------------------X-------C

Stmnt 1 : Total C time 55 min .
With this info cannot find the meeting point whether 1,2 or 3

Stmnt 2 : Both reach at the same time to respective destinations (total distance is same)

Since we know C starts late still covers same distance .
Hence C is speeder is greater than B

Now lets check if stmnt 2 satisfies any of the meeting point

[When they meet they have same time to cover remaining respective distances]

1.) B -------X-------------------------------C

B has to cover larger distance XC and
C has to cover shorter distance XB

But C is faster than B hence it can cover smaller distance before B could cover large distance
hence this meeting point is wrong

2.) B -----------------X--------------------C
Same remaining distance with same time
but since speed is not same
this scenario is also not possible

3.) B --------------------------X-----------C

B has to cover smaller distance XC and
C has to cover Larger distance XB

C can achieve this it as its speed is more B .
So it can reach , till B slowly reaches the studio . This is the only possibility for relative position.
i.e closer B is closer to studio

B