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# c and d are intigers is c even?? 1) c(d+1) = even 2)

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SVP
Joined: 05 Jul 2006
Posts: 1750

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c and d are intigers is c even?? 1) c(d+1) = even 2) [#permalink]

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20 Sep 2008, 10:18
This topic is locked. If you want to discuss this question please re-post it in the respective forum.

c and d are intigers is c even??

1) c(d+1) = even
2) (c+2)(d+4) = even

Kudos [?]: 430 [0], given: 49

Director
Joined: 23 Sep 2007
Posts: 782

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Re: even and odd intigers [#permalink]

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20 Sep 2008, 13:58
yezz wrote:
c and d are intigers is c even??

1) c(d+1) = even
2) (c+2)(d+4) = even

C
statement 1: cd + C = even, insuff
statement 2: 4c + 2d + cd + 8 = even, insuff

together: subtract statement 1 from 2 to get 3c + 2d + 8 = even

2d + 8 must be even, so 3c must also be even, so c is even

Kudos [?]: 236 [0], given: 0

VP
Joined: 05 Jul 2008
Posts: 1402

Kudos [?]: 437 [0], given: 1

Re: even and odd intigers [#permalink]

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20 Sep 2008, 14:06
gmatnub wrote:
yezz wrote:
c and d are intigers is c even??

1) c(d+1) = even
2) (c+2)(d+4) = even

A
statement 1: cd + C = even, c must be even

wrong sum of either two evens or two odds can be even C can be odd too

C (d+1) is even means either one of them is even or both. ( Y and N ) Insuff

(C+2) (D+4) is even means either one of them is even or both. ( Y and N ) Insuff

Combine both Still the same. Hence E

Kudos [?]: 437 [0], given: 1

Senior Manager
Joined: 31 Jul 2008
Posts: 290

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Re: even and odd intigers [#permalink]

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20 Sep 2008, 14:09
C

from 1 c can be odd / even

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VP
Joined: 05 Jul 2008
Posts: 1402

Kudos [?]: 437 [0], given: 1

Re: even and odd intigers [#permalink]

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20 Sep 2008, 14:12
gmatnub wrote:
yezz wrote:
c and d are intigers is c even??

1) c(d+1) = even
2) (c+2)(d+4) = even

C
statement 1: cd + C = even, insuff
statement 2: 4c + 2d + cd + 8 = even, insuff

together: subtract statement 1 from 2 to get 3c + 2d + 8 = even

2d + 8 must be even, so 3c must also be even, so c is even

Yeppers! You nailed it.

Kudos [?]: 437 [0], given: 1

Intern
Joined: 02 Sep 2008
Posts: 45

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Re: even and odd intigers [#permalink]

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20 Sep 2008, 19:05
Yep,

St1: either C or D+1 is even.

St2: either C+2 or D+4 is even.

combining both, D+1 and D+4 both can't be even at one time but C and C+2 has to be even as multiplication is even.

Hence. C is even. and C is the answer

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VP
Joined: 30 Jun 2008
Posts: 1034

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Re: even and odd intigers [#permalink]

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20 Sep 2008, 22:03
Great approaches both Twoone and gmatnub !!
_________________

"You have to find it. No one else can find it for you." - Bjorn Borg

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VP
Joined: 17 Jun 2008
Posts: 1374

Kudos [?]: 406 [0], given: 0

Re: even and odd intigers [#permalink]

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20 Sep 2008, 22:26
yezz wrote:
c and d are intigers is c even??

1) c(d+1) = even
2) (c+2)(d+4) = even

Clearly C

1) says c=even,d=odd
c=odd,d=odd
c=even,d=even
c can be even or odd

2)c=even,d=odd
c=odd,d=even
c=even,d=even

INSUFFI c =even or odd

again combining both we get c=even and d=odd
HENCE SUFFI
IMO C
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Re: even and odd intigers   [#permalink] 20 Sep 2008, 22:26
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