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BrentGMATPrepNow
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Why do you know that 4q+1 = odd?

gmatophobia
"c" can be represented as

c = 4d * q + d

c = d (4q + 1)

q = quotient when c is divided by 4.

Statement 1 : c is even

4q + 1 = odd ; even + odd = odd

So for c to be even d must be even.

Also we know d is a prime number.

The only even prime number is 2. Hence this statement is sufficient.

Statement 2 : c > 4d

c = d (4q + 1)

For different values of q and c we can have different values of d.

Hence, this statement is not sufficient on its own.

Option A
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BrentGMATPrepNow
c is a positive integer, and d is a prime number. When c is divided by 4d, the remainder is d. What is the value of d?

(1) c is even
(2) c > 4d
Given: c is a positive integer, and d is a prime number. When c is divided by 4d, the remainder is d.

-----ASIDE---------------------
There's a nice rule that says, "If N divided by D equals Q with remainder R, then N = DQ + R"
For example, since 17 divided by 5 equals 3 with remainder 2, then we can write 17 = (5)(3) + 2
Likewise, since 53 divided by 10 equals 5 with remainder 3, then we can write 53 = (10)(5) + 3
----------------------------------

Since the quotient isn't given, let's let Q = the quotient when c is divided by 4d.
On other words: When c is divided by 4d, the quotient is Q and the remainder is d
So, from the above rule, we can write: c = (4d)(Q) + d
Factor to get: c = d(4Q + 1)

Target question: What is the value of d?

Statement 1: c is even
Since c = d(4Q + 1), we can conclude that d(4Q + 1) is even.
Since 4Q is even for all integer values of Q, we know that 4Q + 1 is odd
So, if d(4Q + 1) is even, it must be the case that d is even.
Since d is a prime number, d must equal 2 (since 2 is the only even prime).

Statement 2: c > 4d
This information doesn't help us answer the target question.
There are several values of c and d that satisfy statement 2 (and the given information). Here are two:
Case a: c = 10 and d = 2. In this case, the answer to the target question is d = 2
Case b: c = 15 and d = 3. In this case, the answer to the target question is d = 3
Since we can’t answer the target question with certainty, statement 2 is NOT SUFFICIENT

Answer: A

Cheers,
Brent
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Chanovski
Why do you know that 4q+1 = odd?

As 'q' is the quotient, its an integer.

Therefore 4*q is even [ if you're wondering why ? 4 is even , and even * any integer = even ]

1 is odd.

So 4q + 1 = even + odd

even + odd = odd

Therefore 4q + 1 = odd.

Hope this clarifies !
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Chanovski
Why do you know that 4q+1 = odd?
q is an integer
==> 4q is even
==> 4q+1 is odd

- multiply any integer by an even number, we get an even number
- add 1 to any even number, we get an odd number

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