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Can anybody give a good solution to this one?
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without replacement. What is the probability to have two cards of the same suit?
тАв 1/2
тАв 1/3
тАв 1/4
тАв 1/7
тАв 1/8
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without replacement. What is the probability to have two cards of the same suit?
тАв 1/2
тАв 1/3
тАв 1/4
тАв 1/7
тАв 1/8
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Thank you for understanding, and happy exploring!
28 Jul 2003, 21:05
Kudos
Bookmarks
bb
Can anybody give a good solution to this one?
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without replacement. What is the probability to have two cards of the same suit?
тАв 1/2
тАв 1/3
тАв 1/4
тАв 1/7
тАв 1/8
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without replacement. What is the probability to have two cards of the same suit?
тАв 1/2
тАв 1/3
тАв 1/4
тАв 1/7
тАв 1/8
The absolute quickest way to solve this is to say:
Whatever card I pick as the first card, there is only one card of the seven remaining to match its suit. Hence, the answer is 1/7
28 Jul 2003, 22:37
Kudos
Bookmarks
AkamaiBrah
bb
Can anybody give a good solution to this one?
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without replacement. What is the probability to have two cards of the same suit?
тАв 1/2
тАв 1/3
тАв 1/4
тАв 1/7
тАв 1/8
An eight-card deck consists of 4 pairs of each suit. 2 cards are taken at random without replacement. What is the probability to have two cards of the same suit?
тАв 1/2
тАв 1/3
тАв 1/4
тАв 1/7
тАв 1/8
The absolute quickest way to solve this is to say:
Whatever card I pick as the first card, there is only one card of the seven remaining to match its suit. Hence, the answer is 1/7
Very good reasoining!!!
You are the man!
