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# Car A drives from P to Q at a constant rate of 100 km per hour. Afte

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Math Revolution GMAT Instructor
Joined: 16 Aug 2015
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Car A drives from P to Q at a constant rate of 100 km per hour. Afte  [#permalink]

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04 Apr 2018, 01:55
00:00

Difficulty:

25% (medium)

Question Stats:

77% (01:43) correct 23% (02:27) wrong based on 84 sessions

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[GMAT math practice question]

Car A drives from P to Q at a constant rate of 100 km per hour. After car A has driven for 1 hour, train B begins traveling from Q to P at a constant rate of 150 km per hour. If the distance between P and Q is 600 km, then what distance has car A traveled when it meets train B?

A. 200 km
B. 220 km
C. 250 km
D. 270 km
E. 300 km

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"Only $149 for 3 month Online Course" "Free Resources-30 day online access & Diagnostic Test" "Unlimited Access to over 120 free video lessons - try it yourself" Manager Joined: 05 Feb 2016 Posts: 157 Location: India Concentration: General Management, Marketing WE: Information Technology (Computer Software) Re: Car A drives from P to Q at a constant rate of 100 km per hour. Afte [#permalink] ### Show Tags 04 Apr 2018, 02:19 MathRevolution wrote: [GMAT math practice question] Car A drives from P to Q at a constant rate of 100 km per hour. After car A has driven for 1 hour, train B begins traveling from Q to P at a constant rate of 150 km per hour. If the distance between P and Q is 600 km, then what distance has car A traveled when it meets train B? A. 200 km B. 220 km C. 250 km D. 270 km E. 300 km A speed-100 km per hour In one hour Car a travels 100km. Distance left 500km. Time at which both train and car meets=500/(100+150)=2 distance traveled by train= 2*150 =300. E Senior SC Moderator Joined: 22 May 2016 Posts: 2495 Car A drives from P to Q at a constant rate of 100 km per hour. Afte [#permalink] ### Show Tags 04 Apr 2018, 09:17 1 MathRevolution wrote: [GMAT math practice question] Car A drives from P to Q at a constant rate of 100 km per hour. After car A has driven for 1 hour, train B begins traveling from Q to P at a constant rate of 150 km per hour. If the distance between P and Q is 600 km, then what distance has car A traveled when it meets train B? A. 200 km B. 220 km C. 250 km D. 270 km E. 300 km This problem has a couple of potential traps: a) Distance between P and Q $$\neq$$ Distance between A and B; b) A's total distance depends on A's total travel time, including the one hour that A travels alone 1) Find actual distance between A and B Total D between P and Q = 600 km Actual D between A and B = 500 km - A travels alone for 1 hour - A travels (100 kmh * 1hr)= 100 km - A travels toward B, shortens the distance - (600-100) = 500km between them when B starts 2) Find time it takes for A and B to meet Time=D/R, and D=500. We need rate (speed) Opposite directions: ADD speeds of A and B Combined speed = (100 + 150) = 250 kmh Time to meet=D/R: $$\frac{500}{250}$$= 2 hours 3) Total distance that A has traveled? Use A's total time, then multiply by A's rate TOTAL time that A travels Alone: 1 hour To meet B: 2 hours Total time A travels: 3 hours TOTAL distance A travels, RT=D: (100 kmh * 3 hrs) = 300 km Answer E _________________ To live is the rarest thing in the world. Most people just exist. Oscar Wilde VP Joined: 07 Dec 2014 Posts: 1154 Re: Car A drives from P to Q at a constant rate of 100 km per hour. Afte [#permalink] ### Show Tags 04 Apr 2018, 10:21 MathRevolution wrote: [GMAT math practice question] Car A drives from P to Q at a constant rate of 100 km per hour. After car A has driven for 1 hour, train B begins traveling from Q to P at a constant rate of 150 km per hour. If the distance between P and Q is 600 km, then what distance has car A traveled when it meets train B? A. 200 km B. 220 km C. 250 km D. 270 km E. 300 km 1 hour*100 kmh+[500/(100+150)] hours*100 kmh=300 km E Math Revolution GMAT Instructor Joined: 16 Aug 2015 Posts: 6985 GMAT 1: 760 Q51 V42 GPA: 3.82 Re: Car A drives from P to Q at a constant rate of 100 km per hour. Afte [#permalink] ### Show Tags 05 Apr 2018, 23:51 => After car A has driven for 1 hour, the distance between car A and train B is 500 km. Car A and train B approach each other at a speed of 250 km/hr. This means that they will take 2 hours to meet each other. When they meet, car A will have traveled for 3 hours, and have covered a distance of 3 * 100 = 300 km. Therefore, the answer is E. Answer: E It is important that both vehicles will have traveled for the same amount of time after train B has started moving. This gives the equation 100 + 100t + 150t = 600, from which we may deduce that t = 2. Since 100 + 100 *2 = 300, E is the answer. _________________ MathRevolution: Finish GMAT Quant Section with 10 minutes to spare The one-and-only World’s First Variable Approach for DS and IVY Approach for PS with ease, speed and accuracy. "Only$149 for 3 month Online Course"
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Re: Car A drives from P to Q at a constant rate of 100 km per hour. Afte  [#permalink]

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14 Apr 2018, 21:46
MathRevolution wrote:
[GMAT math practice question]

Car A drives from P to Q at a constant rate of 100 km per hour. After car A has driven for 1 hour, train B begins traveling from Q to P at a constant rate of 150 km per hour. If the distance between P and Q is 600 km, then what distance has car A traveled when it meets train B?

A. 200 km
B. 220 km
C. 250 km
D. 270 km
E. 300 km

Speed of Car = 100 km/hr

Let us say time = t

Distance travelled by Car = 100t

Speed of Train = 150 km/hr

Time = t - 1

Distance travelled by Train = 150 (t - 1)

Total distance = 600 kms

So, 600 = 100t + 150t - 150

750 = 250t

t = 3

Therefore, distance travelled by Car when it meets Train = 3 * 100 = 300 kms

(E)
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Re: Car A drives from P to Q at a constant rate of 100 km per hour. Afte   [#permalink] 14 Apr 2018, 21:46
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