Summer is Coming! Join the Game of Timers Competition to Win Epic Prizes. Registration is Open. Game starts Mon July 1st.

 It is currently 17 Jul 2019, 19:43 ### GMAT Club Daily Prep

#### Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

#### Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.  # Car X and Car Y traveled the same 80-mile route. If Car X to

Author Message
TAGS:

### Hide Tags

Manager  Joined: 22 Aug 2013
Posts: 76
Schools: ISB '15
Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

5
4 00:00

Difficulty:   5% (low)

Question Stats: 90% (01:21) correct 10% (01:37) wrong based on 444 sessions

### HideShow timer Statistics Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

_________________
Veritas Prep - 650
MGMAT 1 590
MGMAT 2 640 (V48/Q31)

Originally posted by seabhi on 01 Mar 2014, 05:02.
Last edited by Bunuel on 01 Mar 2014, 06:50, edited 1 time in total.
Edited the question.
Math Expert V
Joined: 02 Sep 2009
Posts: 56277
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

The speed of car X is (distance)/(time) = 80/2 = 40 miles per hour.

The speed of car Y = 3/2*40 = 60 miles per hour --> (time) = (distance)/(speed) = 80/60 = 4/3 hours.

Or: to cover the same distance at 3/2 as fast rate 2/3 as much time is needed --> (time)*2/3 = 2*2/3 = 4/3 hours.

_________________
Intern  Joined: 12 Mar 2016
Posts: 9
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

As Y traveled 50 percent faster than X
So, if X needs 1.5 hour Y needs 1 hour
if X needs 2 hour Y needs 2/1.5 hour = 4/3 hour

Senior Manager  S
Joined: 24 Oct 2016
Posts: 255
Location: India
Schools: IIMB
GMAT 1: 550 Q42 V28 GPA: 3.96
WE: Human Resources (Retail Banking)
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

the distance for both the parties is constant so as we can see that speed of y is multiplied by 3/2 then time will also multiplied by reciprocal of 3/2 which will be 2*2/3= 4/3 time taken by y

hence C
Board of Directors P
Status: QA & VA Forum Moderator
Joined: 11 Jun 2011
Posts: 4512
Location: India
GPA: 3.5
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y travelled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

For Car X -

$$Speed = 40 \ miles/hr$$
$$Time = 2 \ Hours$$

For Car Y -

$$Speed = 60 \ miles/hr$$
$$Time = \frac{80}{60}$$

So, the time required is $$\frac{4}{3}$$ Hours, answer will be (C) $$\frac{4}{3}$$
_________________
Thanks and Regards

Abhishek....

PLEASE FOLLOW THE RULES FOR POSTING IN QA AND VA FORUM AND USE SEARCH FUNCTION BEFORE POSTING NEW QUESTIONS

How to use Search Function in GMAT Club | Rules for Posting in QA forum | Writing Mathematical Formulas |Rules for Posting in VA forum | Request Expert's Reply ( VA Forum Only )
Target Test Prep Representative G
Affiliations: Target Test Prep
Joined: 04 Mar 2011
Posts: 2823
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

We are given that Car X traveled 80 miles in 2 hours. Thus, the rate of car X was 80/2 = 40 mph.

We are also given that Car Y traveled 50% faster than Car X. Thus, Car Y traveled at a rate of 1.5 x 40 = 60 mph.

So, it took Car Y 80/60 = 8/6 = 4/3 hours to travel the route.

_________________

# Jeffrey Miller

Jeff@TargetTestPrep.com

See why Target Test Prep is the top rated GMAT quant course on GMAT Club. Read Our Reviews

If you find one of my posts helpful, please take a moment to click on the "Kudos" button.

CEO  V
Joined: 12 Sep 2015
Posts: 3848
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

Top Contributor
seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

There's a nice rule we can use here.

To set up the rule, recognize that if Y travels 2 times as fast as X, then Y's travel time will be 1/2 of X's.
Similarly, if Y travels 3 times as fast as X, then Y's travel time will be 1/3 of X's.
Or if Y travels 1/4 as fast as X, then Y's travel time will be 4 times X's travel time.

In general, if Y travels a/b times as fast as X, then Y's travel time will be b/a of X's travel time.

So, if Y's speed is 50% more than X's speed, we can say that Y travels 1.5 times as fast as X.
In other words, if Y travels 3/2 times as fast as X, which means Y's travel time will be 2/3 that of X's travel time.

Since X's travel time is 2 hours, Y's travel time will be (2/3)(2) = 4/3 = 1 1/3

Cheers,
Brent
_________________
VP  D
Joined: 09 Mar 2016
Posts: 1273
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

Bunuel wrote:
seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

The speed of car X is (distance)/(time) = 80/2 = 40 miles per hour.

The speed of car Y = 3/2*40 = 60 miles per hour --> (time) = (distance)/(speed) = 80/60 = 4/3 hours.

Or: to cover the same distance at 3/2 as fast rate 2/3 as much time is needed --> (time)*2/3 = 2*2/3 = 4/3 hours.

Does 3/2 mean 50% more ? ---> when you multiply 3/2*40
VP  D
Joined: 09 Mar 2016
Posts: 1273
Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

GMATPrepNow wrote:
seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

There's a nice rule we can use here.

To set up the rule, recognize that if Y travels 2 times as fast as X, then Y's travel time will be 1/2 of X's.
Similarly, if Y travels 3 times as fast as X, then Y's travel time will be 1/3 of X's.
Or if Y travels 1/4 as fast as X, then Y's travel time will be 4 times X's travel time.

In general, if Y travels a/b times as fast as X, then Y's travel time will be b/a of X's travel time.

So, if Y's speed is 50% more than X's speed, we can say that Y travels 1.5 times as fast as X.
In other words, if Y travels 3/2 times as fast as X, which means Y's travel time will be 2/3 that of X's travel time.

Since X's travel time is 2 hours, Y's travel time will be (2/3)(2) = 4/3 = 1 1/3

Cheers,
Brent

hi Brent yes you GMATPrepNow

you say " if Y travels 2 times as fast as X, then Y's travel time will be 1/2 of X's. "

how can that be possible if Y travels twice as fast as X that means for example if Y speed is 30 km per hour and X speed is 15 km per hour. no ?

but you say i need to multiply $$\frac{1}{2}$$* 15 = 7.5 then i get Y =7.5 pls explain CEO  V
Joined: 12 Sep 2015
Posts: 3848
Re: Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

1
Top Contributor
dave13 wrote:
GMATPrepNow wrote:
seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

There's a nice rule we can use here.

To set up the rule, recognize that if Y travels 2 times as fast as X, then Y's travel time will be 1/2 of X's.
Similarly, if Y travels 3 times as fast as X, then Y's travel time will be 1/3 of X's.
Or if Y travels 1/4 as fast as X, then Y's travel time will be 4 times X's travel time.

In general, if Y travels a/b times as fast as X, then Y's travel time will be b/a of X's travel time.

So, if Y's speed is 50% more than X's speed, we can say that Y travels 1.5 times as fast as X.
In other words, if Y travels 3/2 times as fast as X, which means Y's travel time will be 2/3 that of X's travel time.

Since X's travel time is 2 hours, Y's travel time will be (2/3)(2) = 4/3 = 1 1/3

Cheers,
Brent

hi Brent yes you GMATPrepNow

you say " if Y travels 2 times as fast as X, then Y's travel time will be 1/2 of X's. "

how can that be possible if Y travels twice as fast as X that means for example if Y speed is 30 km per hour and X speed is 15 km per hour. no ?

but you say i need to multiply $$\frac{1}{2}$$* 15 = 7.5 then i get Y =7.5 pls explain I think you are mixing up SPEED and TIME

TRUE: If Y travels 2 times as fast as X, then Y's travel time will be 1/2 of X's.

So, if we're talking SPEED, then Y's speed = 30 km per hour and X's speed = 15 km per hour meets the given condition

Now let's compare travel TIMES.
Let's say both cars are traveling 30 km
Then Y's travel TIME = 1 hour and X's travel TIME = 2 hours

Does that help?

Cheers,
Brent
_________________
Senior SC Moderator V
Joined: 22 May 2016
Posts: 3070
Car X and Car Y traveled the same 80-mile route. If Car X to  [#permalink]

### Show Tags

dave13 wrote:
Bunuel wrote:
seabhi wrote:
Car X and Car Y traveled the same 80-mile route. If Car X took 2 hours and Car Y traveled at an average speed that was 50 percent faster than the average speed of Car X, how many hours did it take Car Y to travel the route?

(A) 2/3
(B) 1
(C) 4/3
(D) 8/5
(E) 3

The speed of car X is (distance)/(time) = 80/2 = 40 miles per hour.

The speed of car Y = 3/2*40 = 60 miles per hour --> (time) = (distance)/(speed) = 80/60 = 4/3 hours.

Does 3/2 mean 50% more ? :? ---> when you multiply 3/2*40

Hi dave13 . Yes, 3/2 means 50 percent more.
Why? 3/2 = 1.50, and 1.50 (or 1.5) is the multiplier for "50 percent faster."

Often fractions are easier than decimals in "percent increase/decrease" problems. Just convert the decimal multiplier to a fraction.

Y's rate is a percent increase of X's rate. Here, 50 percent faster =
Original speed + 50% of original speed
--Original speed (X's speed) = 40
--50 percent of 40 = 20
(Original + 50% of original) = (40+20) = 60 = Y
OR

$$Y=1.5X$$
$$1.5=1\frac{5}{10}=1\frac{1}{2}=\frac{3}{2}$$
$$Y = \frac{3}{2}X$$

Here are some common fractions used in percent increase/ decrease problems: 5/4, 6/5, 2/5, 1/4, 1/2, 3/2. Some are increases, some are decreases. Decreases are harder. mikemcgarry explains the issue you asked about here

Hope that helps. _________________
SC Butler has resumed!
Get two SC questions to practice, whose links you can find by date, here.

Tell me, what is it you plan to do with your one wild and precious life? -- Mary Oliver Car X and Car Y traveled the same 80-mile route. If Car X to   [#permalink] 21 Feb 2018, 11:13
Display posts from previous: Sort by

# Car X and Car Y traveled the same 80-mile route. If Car X to  