Car X averages 25.0 miles per gallon of gasoline and Car Y

Question

Car X averages 25 miles per gallon of gasoline and Car Y averages 11.9 miles per gallon. If each car is driven 12,000 miles, approximately how many more gallons of gasoline will Car Y use than Car X ?

(A) 320
(B) 480
(C) 520
(D) 730
(E) 920

Bunuel · Accepted Answer

SOLUTION

Car X averages 25.0 miles per gallon of gasoline and Car Y averages 11.9 miles per gallon. If each car is driven 12,000 miles, approximately how many more gallons of gasoline will Car Y use than Car X ?

(A) 320
(B) 480
(C) 520
(D) 730
(E) 920

(A) 320
(B) 480
(C) 520
(D) 730
(E) 920

Car X will use  \frac{12,000}{25}=480  gallons of gasoline for 12,000 miles;

Car Y will use  \frac{12,000}{(\frac{119}{10})}=12,000*\frac{10}{119}\approx{12,000*\frac{10}{120}}=1,000  gallons of gasoline for 12,000 miles.

The difference is 1,000-480=520 gallons.

Answer: C.

KarishmaB · Answer

Responding to a pm:

Notice what it is given to you:

Car X runs 25 miles in 1 gallon of fuel.
Car Y runs approx 12 miles in 1 gallon of fuel (since options are not close to each other, we can easily approximate 11.9 to 12. If options are very close to each other, you need to calculate a more accurate answer)

So Car X runs an extra 13 miles in one gallon of fuel.

Now what does the term 12000/13 represent? Is it the extra fuel used by car Y? No. This will be the fuel used by a car which runs 12000 miles at an average of 13 miles in one gallon. But neither car X nor car Y does that.

Car X needs 12000/25 = 480 gallons of fuel
Car Y needs 12000/12 = 1000 gallons of fuel

What we need to do here is  \frac{12000}{12} - \frac{12000}{25} . I hope this is obvious to you that this is not equal to  \frac{12000}{(25 - 12)}

When the denominators are different, we cannot combine the fractions. We can combine them in case the denominators are the same. Since 25 and 12 are in the denominator of the quantity we need, we cannot combine them.

ankurjjw · Answer

For simplicity we can assum e 11.9 to b 12, so answer would b 1200/12 -1200/25

Posted from my mobile device

dexerash · Answer

X: 25 miles -------------- in --------------------- 1 gallon
 12000 miles ------------ in -------------------- 12000/25 = 480 gallons

Y: 11.9 miles -------------- in --------------------- 1 gallon
 12000 miles ---------------in -------------------- 12000 / 11.9 gallons
since Q is asking appox value and all options are not very close to each other, so we can assume 11.9 as 12
So, 12000/12 = 1000 gallons

Hence gasoline used by Y - by X = 1000 - 480 = 520

Hence C

GMATPill · Answer

Just think distance = rate * time
12,000 miles = 25mpg * # gallons
12,000 miles = 11.9mpg * # gallons

Similar idea as distance = r*t

So we want to compare # of gallons used.

# gallons X = 12,000 / 25
# gallons Y = 12,000 / 11.9

12,000/11.9 - 12,000/25

~12,000/12 - 12,000/100 *4
1,000 - 120*4
= 1,000 - 480
= 520

(C)

Carcass · Answer

Using R*T=D chart we can arrive to a solution pretty quickly

R T D

car X 25 12000

Car Y 11.9 12000

here is much faster to use 12 instead of 11.9 (also the stem says us the word approximately, whenever we see this word we can rounde some value with attenton)

Car X ---------> T = 12000/25 = 480

Car Y ---------> T = 12000/12= 1000

The difference lead us to C

NOTE: here the trap answer is to think to do 25 - 12 = 13 and then 12000 / 13 = 923.07......that approximately is E

catty2004 · Answer

Thanks for the explanation, but im not sure why using 25 -12 = 13 is equivalent of approximating car Y's distance traveled??

redfield · Answer

Wondering if this is too lazy/simple?

Instead of dividing 12000/25, I just did the approximation of 11.9 to 12 - so quick dividing 12000/12 brings you to 1000 - and just went with an extra approximation saying

12 practically half of 25 so half of 1000 = 500, and since I rounded up the nearest rounded up answer is 520.

It seems like more steps when you write it out but it seemed faster as you can just do that in your head but I'm wondering if, while I arrived at the same answer, this is safe to do a second approximation like that or if on the GMAT that might come back to bite me on problems like these.

KarishmaB · Answer

Approximation is fine if the options are far apart (as in this case). But keep in mind that whenever you approximate, keep the direction in mind. What I mean by that is that if you are going to say that 12 is practically half of 25, so half of 1000 is 500, you need to keep in mind that 12 is "less than" half of 25 so when you divide 12000 by 25, you will get something less than half i.e. less than 500. 
So when you subtract "something less than 500" from 1000, you will get "something more than 500" and that is the reason your answer is 520.

You stumbled in your logic when you said "since I rounded up...". You did round up 25 but it "divides" 12000 so the answer goes down. But thereafter, you need to subtract it from 1000 and that's why you finally "round up"! 
I hope that makes sense.

ScottTargetTestPrep · Answer

To solve this problem we will need to use the formula: rate x gallons = distance, which means:

gallons = distance/rate

We need to calculate the number of gallons used by car X and the number of gallons used by car Y. Let’s start with car X.

For car X we know the following:

rate = 25

distance = 12,000

gallons = 12,000/25 = 480 gallons

For car Y we know the following:

rate = 11.9

Since we are told we can approximate, we can round up the rate of Car Y to 12.

distance = 12,000

gallons = 12,000/12 = 1,000

Thus, we can say that car Y will use approximately 1,000 – 480 = 520 more gallons of gasoline than car X.

The answer is C.

EMPOWERgmatRichC · Answer

Hi All,

This question is ultimately about division. We're told how many miles per gallon each car averages and the distance that each car travels, so we can determine how many gallons of gas each car uses.

Car X: 12,000/25 = 480 gallons

Car Y 12,000/(about 12) = about 1,000 gallons

Approximate difference in gallons used = 1000 - 480 = 520

Final Answer:  C

GMAT assassins aren't born, they're made, 
Rich

Sabby · Answer

Car Y = 12000/ 12 = 1000 (as 11.9 is approximately 12)
Car X = 12000/25= 10000/25 + 2000/25 = 400+80 = 480 ( I broke down the division as I felt a bit overwhelmed. I found it to be a great technique, allowing to keep track of the calculation and it's kinda stress saving)

1000-480=520
Answer C

TomNook · Answer

Here's how I approached this question. They are asking for the difference in gallons of gasoline between Car Y and X.

Car X
 12,000 miles * \frac{1 gallon}{25 miles} = 480 gallons

Car Y
Round 11.9 to 12 to make calculation simpler. Since this question says approximate this should be close.

12,000 miles * \frac{1 gallon}{12 miles} = 1000 gallons

Car Y - Car X = 1000 - 480 = 520 gallons

Thus answer is  C

Abhishek009 · Answer

\frac{12000}{12} - \frac{12000}{25}

=  1000 - 480

=  520 , Answer must be (C)

bumpbot · Answer

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Car X averages 25.0 miles per gallon of gasoline and Car Y

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