Last visit was: 17 Jul 2025, 04:52 It is currently 17 Jul 2025, 04:52
Close
GMAT Club Daily Prep
Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History
Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.
Close
Request Expert Reply
Confirm Cancel
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 17 Jul 2025
Posts: 102,601
Own Kudos:
Given Kudos: 98,220
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,601
Kudos: 742,123
 [52]
Kudos
Add Kudos
50
Bookmarks
Bookmark this Post
Most Helpful Reply
User avatar
Kinshook
User avatar
Major Poster
Joined: 03 Jun 2019
Last visit: 16 Jul 2025
Posts: 5,703
Own Kudos:
5,227
 [6]
Given Kudos: 161
Location: India
GMAT 1: 690 Q50 V34
WE:Engineering (Transportation)
Products:
GMAT 1: 690 Q50 V34
Posts: 5,703
Kudos: 5,227
 [6]
5
Kudos
Add Kudos
1
Bookmarks
Bookmark this Post
General Discussion
User avatar
Chethan92
Joined: 18 Jul 2018
Last visit: 21 Apr 2022
Posts: 914
Own Kudos:
1,442
 [1]
Given Kudos: 95
Location: India
Concentration: Operations, General Management
GMAT 1: 590 Q46 V25
GMAT 2: 690 Q49 V34
WE:Engineering (Energy)
Products:
GMAT 2: 690 Q49 V34
Posts: 914
Kudos: 1,442
 [1]
Kudos
Add Kudos
Bookmarks
Bookmark this Post
avatar
hooolmen
Joined: 19 Jan 2018
Last visit: 22 Feb 2020
Posts: 1
Own Kudos:
6
 [4]
Given Kudos: 55
GMAT 1: 610 Q44 V30
GMAT 1: 610 Q44 V30
Posts: 1
Kudos: 6
 [4]
4
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Don't know why this one felt hard, from the text you get:

(1) \(S = \frac{5C}{4}\)
(2) \(C = \frac{3T}{5} => T = \frac{5C}{3}\)

\(T+S = \frac{5C}{3} + \frac{5C}{4} = \frac{35C}{12}\)

Since C>0, minimum T+S is when C = 12: ans 35 (D).
User avatar
LeoN88
User avatar
BSchool Moderator
Joined: 08 Dec 2013
Last visit: 08 Jul 2025
Posts: 685
Own Kudos:
Given Kudos: 227
Location: India
Concentration: Nonprofit, Sustainability
Schools: ISB '23
GMAT 1: 630 Q47 V30
WE:Operations (Non-Profit and Government)
Products:
Schools: ISB '23
GMAT 1: 630 Q47 V30
Posts: 685
Kudos: 549
Kudos
Add Kudos
Bookmarks
Bookmark this Post
Bunuel
Carla has \(\frac{1}{4}\) more sweaters than cardigans, and \(\frac{2}{5}\) fewer cardigans than turtle­ necks. If she has at least one of each item, what is the minimum total number of turtlenecks plus sweaters that Carla could have?

A. 10
B. 15
C. 20
D. 35
E. 45

Let those types be x and y and z, x+y+z>1, Integers and we have to find x+z

x= y(5/4)

y=z(3/5)

Now we have to make sure all x y and z are Integers and minimum value possible

let z=20, y=12
Then x= 15

x+z Minima= 35
User avatar
shubhim20
Joined: 03 Feb 2025
Last visit: 15 Jul 2025
Posts: 93
Own Kudos:
Given Kudos: 143
Posts: 93
Kudos: 2
Kudos
Add Kudos
Bookmarks
Bookmark this Post
please break down the language if you could don't know why this question seems hard to solve
Chethan92
Sweaters = Cardigans + 1/4*Cardigans
Sweaters = 4/5*Cardigans

Turtleneck = Cardigans - 2/5*Cardigans
Turtleneck = 3/5*Cardigans

Turtleneck + Sweaters = 7/5*Cardigans

Among the answer choices, Only 35 is a multiple of 7.
Hence, D is the answer.
User avatar
Bunuel
User avatar
Math Expert
Joined: 02 Sep 2009
Last visit: 17 Jul 2025
Posts: 102,601
Own Kudos:
742,123
 [1]
Given Kudos: 98,220
Products:
Expert
Expert reply
Active GMAT Club Expert! Tag them with @ followed by their username for a faster response.
Posts: 102,601
Kudos: 742,123
 [1]
1
Kudos
Add Kudos
Bookmarks
Bookmark this Post
shubhim20
please break down the language if you could don't know why this question seems hard to solve
Chethan92
Carla has \(\frac{1}{4}\) more sweaters than cardigans, and \(\frac{2}{5}\) fewer cardigans than turtle­ necks. If she has at least one of each item, what is the minimum total number of turtlenecks plus sweaters that Carla could have?

A. 10
B. 15
C. 20
D. 35
E. 45

Sweaters = Cardigans + 1/4*Cardigans
Sweaters = 4/5*Cardigans

Turtleneck = Cardigans - 2/5*Cardigans
Turtleneck = 3/5*Cardigans

Turtleneck + Sweaters = 7/5*Cardigans

Among the answer choices, Only 35 is a multiple of 7.
Hence, D is the answer.

Given:

  1. Carla has 1/4 more sweaters than cardigans
  2. Carla has 2/5 fewer cardigans than turtlenecks
  3. She has at least one of each item

Let the number of sweaters be s, cardigans be c, and turtlenecks be t

From 1: s : c = 5 : 4
From 2: c : t = 3 : 5

To combine the ratios, match c in both.

Multiply s to c ratio by 3 to get s:t = 15 : 12

Multiply c to t ratio by 4 to get c : t = 12 : 20

So s : c : t = 15 : 12 : 20

Minimum of sweaters plus turtlenecks is 15 + 20 = 35.

Answer is D.
Moderators:
Math Expert
102601 posts
PS Forum Moderator
697 posts