Bunuel
Carla has \(\frac{1}{4}\) more sweaters than cardigans, and \(\frac{2}{5}\) fewer cardigans than turtle necks. If she has at least one of each item, what is the minimum total number of turtlenecks plus sweaters that Carla could have?
A. 10
B. 15
C. 20
D. 35
E. 45
Given: 1. Carla has \(\frac{1}{4}\) more sweaters than cardigans.
2. Carla has \(\frac{2}{5}\) fewer cardigans than turtle necks.
3. She has at least one of each item.
Asked: What is the minimum total number of
turtlenecks plus sweaters that Carla could have?
Let number of sweaters, cardigans and turtle necks be s, c & t respectively
1. Carla has \(\frac{1}{4}\) more sweaters than cardigans.
s:c = 5:4
2. Carla has \(\frac{2}{5}\) fewer cardigans than turtle necks.
c:t = 3:5
s:c:t = 15:12:20
Minimum total number of
turtlenecks plus sweaters that Carla could have = 15 + 20 = 35
IMO D