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27 Sep 2007, 10:57
Kudos
Bookmarks
hello,
I found this problem in the beginners' section and I have some difficulty.
We have 3 cheese balls with diameters of 1, 2, and 6. We melt the cheese balls and make one big cheese ball. What's the diameter of the new cheese ball?
So I understand we need to find the volume of each (4/3*pi*r^3), so
v1=4/3*pi*.5^3 = pi/6
v2=4/3*pi*1^3 = 4*pi/3
v3=4/3*pi*3^3 = 36*pi
so total volume is the sum and = 75*pi/2
so to solve for Diameter we do
4/3*pi*(D/2)^3 = 75*pi/2 well, I don't know how to solve that
the next line in the answer is D^3 = 225, but I am missing the in-between (there is an in-between explanation right?). Would someone be able to help me?
Thanks in advance,
Zaza.
I found this problem in the beginners' section and I have some difficulty.
We have 3 cheese balls with diameters of 1, 2, and 6. We melt the cheese balls and make one big cheese ball. What's the diameter of the new cheese ball?
So I understand we need to find the volume of each (4/3*pi*r^3), so
v1=4/3*pi*.5^3 = pi/6
v2=4/3*pi*1^3 = 4*pi/3
v3=4/3*pi*3^3 = 36*pi
so total volume is the sum and = 75*pi/2
so to solve for Diameter we do
4/3*pi*(D/2)^3 = 75*pi/2 well, I don't know how to solve that
the next line in the answer is D^3 = 225, but I am missing the in-between (there is an in-between explanation right?). Would someone be able to help me?
Thanks in advance,
Zaza.
Archived Topic
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This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
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27 Sep 2007, 11:13
Kudos
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Yes, cancel out pi s from each sides of equation, you will have 4/3*(r^3)=37.5
than multiply each sides by 3/4 than you will be left with,
r^3=225/8 as you know r=d/2 so,
r^3=(d/2)^3=(d^3)/2^3=(d^3)/8=225/8 if you multiply both sides by 8 you will see the last expression left is the same as you showed.
than multiply each sides by 3/4 than you will be left with,
r^3=225/8 as you know r=d/2 so,
r^3=(d/2)^3=(d^3)/2^3=(d^3)/8=225/8 if you multiply both sides by 8 you will see the last expression left is the same as you showed.
27 Sep 2007, 13:33
Kudos
Bookmarks
I understand now. It's the elimination of pi that, for some strange reason, panicked me!!!
Thx for your help...
Thx for your help...
Archived Topic
Hi there,
This topic has been closed and archived due to inactivity or violation of community quality standards. No more replies are possible here.
Where to now? Join ongoing discussions on thousands of quality questions in our Quantitative Questions Forum
Still interested in this question? Check out the "Best Topics" block above for a better discussion on this exact question, as well as several more related questions.
Thank you for understanding, and happy exploring!
