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krishan
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nitya34
The rate of a chemical reaction is directly proportional to concentration of A^2 and inversely proportional to concentration of B. If concentration of B is increased by 100%, which of the following is closest to the percent change in concentration of A, so that the reaction rate remains unchanged.

R(reaction)-->A^2
R--->(1/B)
where
"--> means Proportional too"

Now R -->A^2/B
==>A^2-->B(R is constant)

Now B becomes 2B(100% increase means doubling)
hence New A becomes 41.4 A

hence its D

because root 2=1.414

hence New B becomes

You mean A becomes 1.4A, right?

This is an interesting problem. I also agree the answer should be D, but 1.4^2 is less than 2, so technically, D should not apply as well. :-D
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tharunv
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Thanks for the explanation. That actually makes it more clear.
It's just an approximation - so the answer is correct - 40% increase.
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Yes
we have to find "closest to the percent change "
so 41.4% becomes 40% here :)
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krishan
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thanks a lot. Answer is D.



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