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Chemist: The molecules of a certain weed-killer are always present in

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Chemist: The molecules of a certain weed-killer are always present in  [#permalink]

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New post Updated on: 24 Oct 2017, 01:35
2
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A
B
C
D
E

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  95% (hard)

Question Stats:

53% (02:13) correct 47% (02:22) wrong based on 177 sessions

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Chemist: The molecules of a certain weed-killer are always present in two forms, one the mirror image of the other. One form of the molecule kills weeds, while the other has no effect on them. As a result, the effectiveness of the weed-killer in a given situation is heavily influenced by which of the two forms is more concentrated in the soil, which in turn varies widely because local soil conditions will usually favor the breakdown of one form or the other. Thus, much of the data on the effects of this weed-killer are probably misleading.

Which one of the following, if true, most strengthens the chemist’s argument?

(A) In general, if the molecules of a weed-killer are always present in two forms, then it is likely that weeds are killed by one of those two forms but unaffected by the other.
(B) Almost all of the data on the effects of the weed-killer are drawn from laboratory studies in which both forms of the weed-killer’s molecules are equally concentrated in the soil and equally likely to break down in that soil.
(C) Of the two forms of the weed-killer’s molecules, the one that kills weeds is found in most local soil conditions to be the more concentrated form.
(D) The data on the effects of the weed-killer are drawn from studies of the weed-killer under a variety of soil conditions similar to those in which the weed-killer is normally applied.
(E) Data on the weed-killer’s effects that rely solely on the examination of the effects of only one of the two forms of the weed-killer’s molecules will almost certainly be misleading.

Source: LSAT

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Originally posted by Akela on 24 Oct 2017, 00:49.
Last edited by Akela on 24 Oct 2017, 01:35, edited 1 time in total.
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Re: Chemist: The molecules of a certain weed-killer are always present in  [#permalink]

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New post 24 Oct 2017, 01:26
I answered E.

From the argument, I understand that the soil will remain only one form of the weed-killers, so much of the data on the effects of this weed-killer are probably misleading. Choice E which says that data on the weed-killer’s effects that rely on one form will almost certainly be misleading will strengthen the conclusion of argument.

Could someone help explain it?
Thanks in advance.
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Chemist: The molecules of a certain weed-killer are always present in  [#permalink]

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New post 24 Oct 2017, 01:37
B it is. I solved it by eliminating.

A - "In general" is not definite
C and D, supports, but does not provide definite support on both (about 2 diff type of molecule) types of claims made by chemist.
E - Irrelevant.

B is the only one, which provided data: that in lab, the experiments conducted used soil with equal concentration of both type of molecule and with no discrimination in conditions for breaking of both molecule. Hence if one type of molecule break fast and only the other has high concentration left, this will impact weed killing. Which is the same as what author mentioned. Hope this helps.
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Re: Chemist: The molecules of a certain weed-killer are always present in  [#permalink]

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New post 25 Oct 2018, 23:17
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Re: Chemist: The molecules of a certain weed-killer are always present in &nbs [#permalink] 25 Oct 2018, 23:17
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Chemist: The molecules of a certain weed-killer are always present in

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