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Chloe drove to her friend's house at an average speed of 60 miles per

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Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 09 May 2017, 03:05
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A
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Question Stats:

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Chloe drove to her friend's house at an average speed of 60 miles per hour. She returned by the same route at an average speed of 45 miles per hour. What was the distance to her friend's house and back?

(1) Chloe stopped for 12 minutes on the way to her friend's house for gasoline and candy.
(2) The trip took one hour longer on the way home than on the way there.

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Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 09 May 2017, 04:15
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From the question stem, we have the Chloe's average speed to(60 miles/hour) and from(45 miles/hour) her friends house.
We have been asked to find out the distance between her home and her friends house.

(1) Chloe stopped for 12 minutes on the way to her friend's house for gasoline and candy.
Knowing how much time Chloe stopped at her friends house is not enough to determine the distance.
Hence, insufficient.

(2) The trip took one hour longer on the way home than on the way there.
If the distance traveled(one way) is x
\(\frac{x}{45} - \frac{x}{60} = 1\)
Using this information we can find the distance. Clearly sufficient. (Option B)
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Re: Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 09 May 2017, 11:40
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stat1: not suff,,, no inof about speed can be deduced....

stat2: difference between time is given...
can be caluclated,,, suff

ans B
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Re: Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 11 Jul 2017, 16:53
Given data,
Speed on the way there: 60 mph
Speed on the way back: 45 mph

Looking for:
What was total distance?

Statement 1: No other details given other than one stop; insufficient.
Statement 2:

It took 1 hour longer on the way back than there so...

60*t= 45*(t+1)
60t=45t+45
15t=45
t=3

d= r*t
d= 60*3= 180 miles

Sufficient.
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Re: Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 11 Jul 2017, 18:33
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We need to find the distance and we have 2 speed. So we need to find the time taken for the trip or difference in the time for both the trip.

A. Says only one stop. No other information.
B. Says exactly what we wanted. So B is correct.
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Re: Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 05 Sep 2017, 17:45
Hi Bunuel !

From the stimulus in statement 2: THE TRIP TOOK... , how can we deduce the amount of time that statement 2 is referring is not comprising time for rest or stop?

Many thanks :)
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Re: Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 05 Sep 2017, 21:31
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leanhdung wrote:
Hi Bunuel !

From the stimulus in statement 2: THE TRIP TOOK... , how can we deduce the amount of time that statement 2 is referring is not comprising time for rest or stop?

Many thanks :)


Actually this does not matter. We know the average rates: (average rate) = (total distance)/(total time). (total time) consists of the total time spent to cover that distance, with all the stops and everything.
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Re: Chloe drove to her friend's house at an average speed of 60 miles per  [#permalink]

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New post 05 Apr 2019, 11:30
Given: 60 * x = d
and 45 * y = d
Find: 2d = ?

1) We have 2 variables for time, we can't relate them. The fact that she stopped doesn't give us any additional info.

2) y+1 = x, now we have another equation and can solve.
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Re: Chloe drove to her friend's house at an average speed of 60 miles per   [#permalink] 05 Apr 2019, 11:30
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