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Great solutions above! Here's a slightly different way to think about this that some of you might find faster on test day.

Key Concept: Combined Work Rates with a Worker Leaving Midway

1. Find individual rates as fractions of the job per day.
Clara's rate = 1/48 per day
Hugo's rate = 1/32 per day

2. Find their combined rate.
Together = 1/48 + 1/32
To add these, use LCD of 96:
= 2/96 + 3/96 = 5/96 per day

3. Calculate work done in the first 8 days (both working).
Work completed = 8 × 5/96 = 40/96 = 5/12

4. Find remaining work.
Remaining = 1 − 5/12 = 7/12

5. Calculate how long Clara takes to finish alone.
Time = Remaining work ÷ Clara's rate = (7/12) ÷ (1/48) = (7/12) × 48 = 7 × 4 = 28 days

Answer: A (28)

The common trap here: Many students calculate the total combined time (how long both would take to finish the entire job together) and then subtract 8, which gives a wrong answer. The question isn't asking how much faster they'd finish together — it's asking what happens when one person leaves partway through. You have to split the problem into two phases: the "together" phase and the "alone" phase.

Quick mental math shortcut: Once you see that 5/12 of the work is done, the remaining 7/12 is just 7 × (48/12) = 7 × 4 = 28. Recognizing that 48 is divisible by 12 saves you from messy fraction division under time pressure.

Takeaway: For any work-rate problem where workers join or leave partway through, always split the timeline into phases — calculate work done in each phase separately, then handle the leftover.
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