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27 Nov 2023, 23:00
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Walkabout
Responding to a pm: The question tests our understanding of remainders.
Say there are n members. If we take away 3 of the members, the other members can sit either in groups of 4 completely or in groups of 5 completely. So the number of the rest of the members is a multiple of 4 and 5 i.e. 20. Hence number of members can be 23 or 43 or 63 or 83 etc. But since number of members cannot be more than 40, w must have 23 members.
When we divide 23 by 6, we get 5 remainder. So 5 people must sit on the last table.
Answer (E)
Check this video for this concept of remainders: https://youtu.be/A5abKfUBFSc
02 Dec 2023, 02:39
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its whole based on understanding actually
as we know Dividend=Divisor*Quotient+Remainder
Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables
Let's take the 1 scenario; the remainder is 3 and Divisor is 4
Dividend = 4*Q1+3
sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables
The second scenario is again the remainder is 3 divisor is 5
Dividend =5*Q2+3 ,,
Equate 4*Q1+3=5Q2+3
4Q1=5Q2 now you can find Q1=5 Q2=4 as dividend is X Put the value of q1 and q2 X=23
as we know Dividend=Divisor*Quotient+Remainder
Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables
Let's take the 1 scenario; the remainder is 3 and Divisor is 4
Dividend = 4*Q1+3
sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables
The second scenario is again the remainder is 3 divisor is 5
Dividend =5*Q2+3 ,,
Equate 4*Q1+3=5Q2+3
4Q1=5Q2 now you can find Q1=5 Q2=4 as dividend is X Put the value of q1 and q2 X=23
11 Dec 2025, 16:53
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