GMAT Question of the Day - Daily to your Mailbox; hard ones only

It is currently 17 Jan 2019, 11:21

Close

GMAT Club Daily Prep

Thank you for using the timer - this advanced tool can estimate your performance and suggest more practice questions. We have subscribed you to Daily Prep Questions via email.

Customized
for You

we will pick new questions that match your level based on your Timer History

Track
Your Progress

every week, we’ll send you an estimated GMAT score based on your performance

Practice
Pays

we will pick new questions that match your level based on your Timer History

Not interested in getting valuable practice questions and articles delivered to your email? No problem, unsubscribe here.

Close

Request Expert Reply

Confirm Cancel
Events & Promotions in January
PrevNext
SuMoTuWeThFrSa
303112345
6789101112
13141516171819
20212223242526
272829303112
Open Detailed Calendar
  • The winning strategy for a high GRE score

     January 17, 2019

     January 17, 2019

     08:00 AM PST

     09:00 AM PST

    Learn the winning strategy for a high GRE score — what do people who reach a high score do differently? We're going to share insights, tips and strategies from data we've collected from over 50,000 students who used examPAL.
  • Free GMAT Strategy Webinar

     January 19, 2019

     January 19, 2019

     07:00 AM PST

     09:00 AM PST

    Aiming to score 760+? Attend this FREE session to learn how to Define your GMAT Strategy, Create your Study Plan and Master the Core Skills to excel on the GMAT.

Club X has more than 10 but fewer than 40 members. Sometimes the membe

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  
Author Message
TAGS:

Hide Tags

 
Senior PS Moderator
User avatar
V
Joined: 26 Feb 2016
Posts: 3334
Location: India
GPA: 3.12
Premium Member CAT Tests
Re: Club X has more than 10 but fewer than 40 members. Sometimes the membe  [#permalink]

Show Tags

New post 27 Feb 2018, 08:58
adkikani wrote:
Quote:
Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


pushpitkc niks18 Hatakekakashi

What is wrong with below thinking?

I know my total members in X have to be between 11 and 39.
Quote:
Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables,

9*4 = 36
1*3 = 3
Total = 39 . .. . .(1)

Quote:
and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables

7*5 = 35
1*3 = 3
Total =38 .. ... .(2)

Do i need to perform trial and error to make (1) = (2) ?


adkikani

Without having a common number of the members of the club, it is not possible to solve this
problem. So, yes it is necessary for us to have a unique number of the members of the club.

However, we don't need to perform trial and error to arrive at such a number.
In the range 10 < x < 40
Case 1: 11,15,19,23,27,31,35,39 are possible of form 3x + 4
Case 2: 13,18,23,28,33,38 are possible of form 5x + 3

The only overlap happens at 23 and can be assumed to be the number of people at the club.
_________________

You've got what it takes, but it will take everything you've got

Retired Moderator
avatar
D
Joined: 25 Feb 2013
Posts: 1220
Location: India
GPA: 3.82
GMAT ToolKit User Premium Member Reviews Badge
Re: Club X has more than 10 but fewer than 40 members. Sometimes the membe  [#permalink]

Show Tags

New post 27 Feb 2018, 09:29
adkikani wrote:
Quote:
Club X has more than 10 but fewer than 40 members. Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables, and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables. If they sit at tables with 6 members at each table except one and fewer than 6 members at that one table, how many members will be at the table that has fewer than 6 members?

(A) 1
(B) 2
(C) 3
(D) 4
(E) 5


pushpitkc niks18 Hatakekakashi

What is wrong with below thinking?

I know my total members in X have to be between 11 and 39.
Quote:
Sometimes the members sit at tables with 3 members at one table and 4 members at each of the other tables,

9*4 = 36
1*3 = 3
Total = 39 . .. . .(1)

Quote:
and sometimes they sit at tables with 3 members at one table and 5 members at each of the other tables

7*5 = 35
1*3 = 3
Total =38 .. ... .(2)

Do i need to perform trial and error to make (1) = (2) ?


Hi adkikani

As you rightly mentioned that total number of members have to be in the range 11 to 39.

In the first scenario we have 3 member at One table and 4 members at other let's say \(x\) tables

So number of members will be \(= 4x+3\)

In the second scenario we have 3 member in One table and 5 members at other let's say \(y\) tables

So from this we have number of members \(= 5y+3\)

but number of members in both scenarios has to be equal so \(4x+3=5y+3=>4x=5y\)

Now in the given range there is only one possibility for the above equation to hold true \(4x=5y=20\).

Hence number of members \(= 20+3=23\)

In your method you will have to form two sets as per the given relationship and then find the common value, which will be 23
Manager
Manager
User avatar
B
Joined: 14 Feb 2017
Posts: 122
Location: Australia
Concentration: Technology, Strategy
GMAT 1: 560 Q41 V26
GMAT 2: 550 Q43 V23
GPA: 2.61
WE: Management Consulting (Consulting)
CAT Tests
Re: Club X has more than 10 but fewer than 40 members. Sometimes the membe  [#permalink]

Show Tags

New post 05 Dec 2018, 22:24
x = number of members

x-3 is divisible by 4
x-3 is divisible by 5

If x-3 is divisible by 4 and 5 it must also be divisible by the LCM(4,5), which is 20.

Thus (x-3)/20 = (some Integer)
x-3 = 20(*some integer*)
X = 20(*some integer*) + 3
lets test values
x = 20(1) + 3 = 23
x = 20 (2) + 3 = 43 wait... this is outside the range of 10<x<40, so x must be 23

Thus 23/6 = 3 remainder 5
GMAT Club Bot
Re: Club X has more than 10 but fewer than 40 members. Sometimes the membe &nbs [#permalink] 05 Dec 2018, 22:24

Go to page   Previous    1   2   [ 23 posts ] 

Display posts from previous: Sort by

Club X has more than 10 but fewer than 40 members. Sometimes the membe

  new topic post reply Question banks Downloads My Bookmarks Reviews Important topics  


Copyright

GMAT Club MBA Forum Home| About| Terms and Conditions and Privacy Policy| GMAT Club Rules| Contact| Sitemap

Powered by phpBB © phpBB Group | Emoji artwork provided by EmojiOne

Kindly note that the GMAT® test is a registered trademark of the Graduate Management Admission Council®, and this site has neither been reviewed nor endorsed by GMAC®.