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# Company J can build 36 houses in a year. Company K also builds houses.

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Math Expert
Joined: 02 Sep 2009
Posts: 56300
Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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14 Mar 2017, 23:05
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Difficulty:

5% (low)

Question Stats:

94% (01:01) correct 6% (01:58) wrong based on 82 sessions

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Company J can build 36 houses in a year. Company K also builds houses. How long will it take both companies working simultaneously at their individual rates to build 75 houses?

(1) Company K is capable of building 14 houses every 3 months.
(2) Last year at one point, Company K was working on four houses at the same time.

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Intern
Joined: 12 Aug 2013
Posts: 46
Re: Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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14 Mar 2017, 23:19
Company J Rate :- 1 house in 1/36 year
stmt 1 :- 14 houses in 3 months :- 56 houses in a year
Rate of building 1 house = 1/56 year
both can build 1 house in (1/36+ 1/56) year
75 houses can be calculated..hence sufficient

stmt2 - does not say anything about the constant rate and for duration K was working on 4 houses.Not sufficient.

Should be A...not sure though
Director
Joined: 21 Mar 2016
Posts: 518
Re: Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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15 Mar 2017, 00:29
stat A luks sufficient

any body plz help
Director
Status: Come! Fall in Love with Learning!
Joined: 05 Jan 2017
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Location: India
Re: Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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15 Mar 2017, 01:07
total is 75 houses
rate of J is 36 houses/year
rate of K is unknown. let it be k
so the time taken will be 75/(36+k)

therefore, we need to find k

St 1: k builds 14 houses in 3 months. therefore no. of houses k builds in 1 year or 12 months = 14*4 = 56houses/year = k. Hence the value for the above expression can be calculated. ANSWER

St 2: the value of k cannot be deduce with the help of this information.

Option A
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Posts: 243
Re: Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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15 Mar 2017, 10:43
(1) We know that company J can build 36 houses in a year and we know that company k can build 42 houses in a year. Therefore, we can calculate how long it will take both companies working simultaneously at their individual rates to build 75 houses.
1/42 + 1/36 =
Sufficient

(2) We do not know how many company k can build in year.
Insufficient

Senior Manager
Joined: 16 Nov 2016
Posts: 274
Re: Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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15 Mar 2017, 11:06
We are given rate of company J, i.e 36 houses/year
We need to find out total time taken to build 75 houses if both J and K work simultaneously.

Rate*Time=Work

1/36=rate of J
k= rate of company K
total time taken be t

1/36+k * t=75

so basically we need to know the rate of company k

st.1 tells us the rate of company k, hence sufficient

st.2 does not give us any relevant info.

therefore ans is a.
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Joined: 21 Nov 2015
Posts: 16
Concentration: Finance, Economics
Schools: Erasmus '20
Re: Company J can build 36 houses in a year. Company K also builds houses.  [#permalink]

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27 Aug 2018, 08:52
We have a rate of J, hence why we need a rate of K
1. 14houses – 3 months – SUFF
2. For what time? – UNSUFF
A
Re: Company J can build 36 houses in a year. Company K also builds houses.   [#permalink] 27 Aug 2018, 08:52
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