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24 Oct 2007, 01:19
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Can someone explain the concept from MGMAT page 85?
Given the ascending set [X, X, Y, Y, Y, Y] what is greater, median or mean?
median is Y.
Avg = sum/N
Avg = (2x + 4y) / 6
"When solving average problems, it is better to deal with the sum of the terms than their average. If the mean were greater than the median, the sum would be greater than 6y. So the question is really, is (2x + 4y) < 6y?
Since X is less than Y, (2x + 4y) is less than 6y. Therefore, mean < Y.
Given that the median is Y, the mean is less than Y, the median is greater than the mean."
Where did they get 6y from?
Given the ascending set [X, X, Y, Y, Y, Y] what is greater, median or mean?
median is Y.
Avg = sum/N
Avg = (2x + 4y) / 6
"When solving average problems, it is better to deal with the sum of the terms than their average. If the mean were greater than the median, the sum would be greater than 6y. So the question is really, is (2x + 4y) < 6y?
Since X is less than Y, (2x + 4y) is less than 6y. Therefore, mean < Y.
Given that the median is Y, the mean is less than Y, the median is greater than the mean."
Where did they get 6y from?
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24 Oct 2007, 05:40
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bmwhype2
They are checking whether AVG < Y
since AVG = (2x + 4y) / 6 we have to check whether (2x + 4y) / 6 < y
which is equivalent to (2x + 4y) < 6y
Hope I helped ...
24 Oct 2007, 09:11
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this little picture of family income is very good for understanding difference between average (= mean), median and mode...
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USA family income.jpg [ 229.08 KiB | Viewed 4067 times ]
