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Vavali
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iamcartic
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buffdaddy
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I apologise

it's 5^21 x 4^11 = 2 x 10^n
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jallenmorris
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Then the answer is n = 21.

Explanation:

When you have exponents, you can multiply the base of the exponent ONLY IF THE EXPONENT IS THE SAME NUMBER!!

Example: \(2^3 * 6^3 = 12^3\)

Furthermore, if you see that 4 is a multiple of 2, then you can make the base 2 rather than 4, but you must change the exponent or the value will be different. In this instance, you would double the value of the exponent from 11 to 22. because \(4^{11} = 2^{22}\).

This can be done with any perfect square of the base. (i.e., \(9^6 = 3^{12}\)). Note that 9 is the square of 3. You could also do this with \(27^3 = 3^9\).

So, now we have

\(5^{21} * 2^{22}\)

In order to make the exponent the same, pull out a 2. So we then would have
\(5 ^{21} * 2 * 2^{21}\) Now the base of 5 and 2 can be multiplied while keeping the same exponent. The result is:

\(2 * 10^{21}\) n = 21.

Vavali
I apologise

it's 5^21 x 4^11 = 2 x 10^n
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gmatnub
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n=21

The other posters showed the method.
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method with correct values

\({5}^{21}* {4}^{11} = {2}*{10}^{n}\)
--> \({5}^{21}*{2}^{22} = {2}*{5*2}^{n}\)
--> = \({2}*{5}^{n}*{2}^{n}\)
--> \({5}^{21}*{2}^{22} = {5}^{n}*{2}^{n+1}\)

n=21
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The others showed the method, but didn't really explain why some of the things work the way they do.



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