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24 Oct 2008, 15:42
Kudos
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Hi all,
Pls help me with this problem?
List 6 factors of the product of 5 consecutive even intergers?
My answer is: the six factors of this products will be 1 and the 5 consecutive even integers themselves. Is that right?
Ex: the 5 consecutive even integers are: 2, 4, 6, 8, 10.
So the 6 factors of this product will be: 1, 2, 4, 6, 8, 10.
There is a different explanation in the MGMAT - Number Properties. I understand the explanation but want to check to see if my understanding is right or wrong.
Thanks much.
Pls help me with this problem?
List 6 factors of the product of 5 consecutive even intergers?
My answer is: the six factors of this products will be 1 and the 5 consecutive even integers themselves. Is that right?
Ex: the 5 consecutive even integers are: 2, 4, 6, 8, 10.
So the 6 factors of this product will be: 1, 2, 4, 6, 8, 10.
There is a different explanation in the MGMAT - Number Properties. I understand the explanation but want to check to see if my understanding is right or wrong.
Thanks much.
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24 Oct 2008, 21:43
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nganle08
Yes you are right. The product of 5 different numbers will have at least the 5 numbers as factors plus the number 1, which is a factor of all numbers
25 Oct 2008, 01:02
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Does the question imply anything about which set of the 6 factors.
Because In ur example 2,4,6,8,9 the product is 2^7*3^3 which has (7+1)*(3+1)= 32 factors. Out of these 32 factors we can make 32!/30!*6! sets that have 6 members each.
Because In ur example 2,4,6,8,9 the product is 2^7*3^3 which has (7+1)*(3+1)= 32 factors. Out of these 32 factors we can make 32!/30!*6! sets that have 6 members each.
26! it is . 
