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Consider the formula H = 2a^3/b. If a is doubled and b is increased

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Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 03 Dec 2015, 06:30
00:00
A
B
C
D
E

Difficulty:

  25% (medium)

Question Stats:

69% (00:46) correct 31% (01:28) wrong based on 115 sessions

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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 03 Dec 2015, 06:43
after applying ----------- stated in question

H' = 2*(2a)^3/4b
H' = 2*8a^3/4b
H' = 8/4(H)
H' = 2 H
Thus A
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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 03 Dec 2015, 07:29
H = (2a^3)/b
if a is doubled and b is incresead by factor of 4 then equation becomes
H = [2*(2a)^3] / 4b
H = 16a^3 / 4b
H = 4a^3 / b

Initially H = (2a^3) / b, Now H = (4a^3) / b which means H has been increased by a factor of 2.

Answer = A = 2
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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 03 Dec 2015, 08:01
A..

h= 2 (8) A^3/(4) B

HENCE A
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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 06 Sep 2018, 18:18
The question formation is wrong, when we are saying that "b" is increased by a factor of 4 ,this means that my new b will be b+4k form. If the question formed was b is increased to a factor of 4 then b will be 4k. If the answer to the question has to be A.2 then b must be written simply become 4 times.
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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 07 Sep 2018, 06:31
I agree I also interpreted the question as b+4b...I would like to know what is wrong with my thinking...thanks.

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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 08 Sep 2018, 04:58
Bunuel wrote:
Consider the formula \(H = \frac{2a^3}{b}\). If a is doubled and b is increased by a factor of 4, by what factor is H increased?

A. 2
B. 4
C. 6
D. 8
E. 16




Hi Bunel, b is increased by factor k means bk + k or bk ?

was stuck by this for some time
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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 08 Sep 2018, 05:00
LoneSurvivor wrote:
The question formation is wrong, when we are saying that "b" is increased by a factor of 4 ,this means that my new b will be b+4k form. If the question formed was b is increased to a factor of 4 then b will be 4k. If the answer to the question has to be A.2 then b must be written simply become 4 times.


checkout this link

https://www.beatthegmat.com/word-transl ... 12477.html
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Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased  [#permalink]

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New post 09 Sep 2018, 03:19
H=\(\frac{2a^3}{b}\) --> H= \(\frac{a^3}{b}\)*2

The increase results in the following equation:

\(\frac{2*(2a)^3}{4b}\) --> \(\frac{16a^3}{4b}\) --> \(\frac{4a^3}{b}\) --> \(\frac{a^3}{b}\)*4
2*2=4 Hence, A.
Re: Consider the formula H = 2a^3/b. If a is doubled and b is increased &nbs [#permalink] 09 Sep 2018, 03:19
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