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05 Nov 2005, 23:14
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Cool_Johnny here's a question I created...
Rectangle ABCD has a width of 2.25, and length CD is a subset of values of the infinite set of values in equation Y=0. Rectangle ABCD also has three points in common with parabola Y=X^2-4X+1.75, which has exactly 2 points in common with equation Y=0. If the difference between the two common points of parabola Y=X^2-4X+1.75 and line Y=0 equals the range of values in common between rectangle side CD and line Y=0 then what is the area of rectangle ABCD?
A)6.25
B)6.75
C)7.0
D)7.25
E)9.0
Please Allow COol_JoHnnY to POst HiS ansWEr FirsT! Thank YOu! :rotate
Rectangle ABCD has a width of 2.25, and length CD is a subset of values of the infinite set of values in equation Y=0. Rectangle ABCD also has three points in common with parabola Y=X^2-4X+1.75, which has exactly 2 points in common with equation Y=0. If the difference between the two common points of parabola Y=X^2-4X+1.75 and line Y=0 equals the range of values in common between rectangle side CD and line Y=0 then what is the area of rectangle ABCD?
A)6.25
B)6.75
C)7.0
D)7.25
E)9.0
Please Allow COol_JoHnnY to POst HiS ansWEr FirsT! Thank YOu! :rotate
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05 Nov 2005, 23:56
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ok leme try ....
Width 2.25 , so to calculate the area of need length
two points are common between parabola and line so
X^2-4X+1.75=0
(x-.5)(x-3.5)=0
x=.5 and X=3.5 both of these points line on line Y=0
so length = 3.5 - .5 = 3
area = 2.25*3 = 6.75
Am i Right .....
RK
thanx man for creating the question ..for me ..appreciate your effort
06 Nov 2005, 01:04
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Titleist
The bold part means CD is also the two roots of equation
x^2-4X+1.75= 0 ------> There can only be TWO intersections between the rectangle and the parabola. If not, please show me the exception
...It's when the nadir of the parabola touches AB ...and ABCD belongs to the area below the x-axis( CD lies on x-axis)
