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Rectangle ABCD has a width of 2.25, and length CD is a subset of values of the infinite set of values in equation Y=0. Rectangle ABCD also has three points in common with parabola Y=X^2-4X+1.75, which has exactly 2 points in common with equation Y=0. If the difference between the two common points of parabola Y=X^2-4X+1.75 and line Y=0 equals the range of values in common between rectangle side CD and line Y=0 then what is the area of rectangle ABCD?
A)6.25
B)6.75
C)7.0
D)7.25
E)9.0
Please Allow COol_JoHnnY to POst HiS ansWEr FirsT! Thank YOu! :rotate
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Hi there,
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Width 2.25 , so to calculate the area of need length
two points are common between parabola and line so
X^2-4X+1.75=0
(x-.5)(x-3.5)=0
x=.5 and X=3.5 both of these points line on line Y=0
so length = 3.5 - .5 = 3
area = 2.25*3 = 6.75
Am i Right ..... RK
thanx man for creating the question ..for me ..appreciate your effort
Rectangle ABCD has a width of 2.25, and length CD is a subset of values of the infinite set of values in equation Y=0. Rectangle ABCD also has three points in common with parabola Y=X^2-4X+1.75, which has exactly 2 points in common with equation Y=0. If the difference between the two common points of parabola Y=X^2-4X+1.75 and line Y=0 equals the range of values in common between rectangle side CD and line Y=0 then what is the area of rectangle ABCD?
A)6.25 B)6.75 C)7.0 D)7.25 E)9.0
Please Allow COol_JoHnnY to POst HiS ansWEr FirsT! Thank YOu!
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The bold part means CD is also the two roots of equation
x^2-4X+1.75= 0 ------> There can only be TWO intersections between the rectangle and the parabola. If not, please show me the exception
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