The answer is B.
This is how:
Draw a perpendicular line from the point P onto X-axis. Lets call the point of intersection as A. Now we have a 30-60-90 Right Triangle POA. PA=1. AO=

. PO = 2 = QO. (OP = OQ = radius of circle).
This is 1:2:

triangle. Angle POA=30 degrees.
Draw a perpendicular line from the point Q onto X-axis. Lets call that point of intersection as B. QBO is a 30-60-90 Right Triangle as well.
Extend the line PO and QO. Using Vertical Angles theorem (Opposite angles), you know Angle QOB = 60.
We know the ratio of a 30-60-90 Right Triangle to be 1:2:

.
We know QO = 2. Thus, OB = 1 = s.
s=1.
Although it seems complicated, once you extend the line segments PO and QO and find out all the angles, the problem becomes simple.
Remembering the ratio of the sides of a 30-60-90 Right Triangle and 45-45-90 Right Triangle is very handy for GMAT.
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