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07 Sep 2013, 22:24
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Difficulty:
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Question Stats:
80% (01:22) correct
20%
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Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent of the original cost?
(A) 200
(B) 600
(C) 800
(D) 1600
(E) 50
I read the explanation in Manhattan but cant relate to it.
I worked it out this way
Assume,
t=1
b=2
Original = (1*2)^4= 16
New= (1*2*2)^4 = 256
% change= (change/Original)*100
=(240/16)*100
=1500
Where am I going wrong?
Thanks
(A) 200
(B) 600
(C) 800
(D) 1600
(E) 50
I read the explanation in Manhattan but cant relate to it.
I worked it out this way
Assume,
t=1
b=2
Original = (1*2)^4= 16
New= (1*2*2)^4 = 256
% change= (change/Original)*100
=(240/16)*100
=1500
Where am I going wrong?
Thanks
07 Sep 2013, 22:30
Kudos
Bookmarks
theGame001
Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent
of the original cost?
(A) 200
(B) 600
(C)800
(D) 1600
(E) 50
I read the explanation in Manhattan but cant relate to it.
I worked it out this way
Assume,
t=1
b=2
Original = (1*2)^4= 16
New= (1*2*2)^4 = 256
% change= (change/Original)*100
=(240/16)*100
=1500
Where am I going wrong?
Thanks
of the original cost?
(A) 200
(B) 600
(C)800
(D) 1600
(E) 50
I read the explanation in Manhattan but cant relate to it.
I worked it out this way
Assume,
t=1
b=2
Original = (1*2)^4= 16
New= (1*2*2)^4 = 256
% change= (change/Original)*100
=(240/16)*100
=1500
Where am I going wrong?
Thanks
The question asks for the relative percent b/w the new cost and the final cost, that is \(\frac{256}{16}*100\) and NOT the precent increase/decrease.
For example, initial cost=1 , final cost = 2, and the question asks what percent of the original cost is the final cost : \(\frac{2}{1}*100\) = 200%
Again, if the question asks, what is the percent increase between the final and the initial cost : \(\frac{2-1}{1}*100\) = 100%
07 Sep 2013, 22:56
Kudos
Bookmarks
theGame001
Cost is expressed by the formula tb^4. If b is doubled, the new cost is what percent
of the original cost?
(A) 200
(B) 600
(C)800
(D) 1600
(E) 50
I read the explanation in Manhattan but cant relate to it.
I worked it out this way
Assume,
t=1
b=2
Original = (1*2)^4= 16
New= (1*2*2)^4 = 256
% change= (change/Original)*100
=(240/16)*100
=1500
Where am I going wrong?
Thanks
Original Cost C1=t1*b1^4of the original cost?
(A) 200
(B) 600
(C)800
(D) 1600
(E) 50
I read the explanation in Manhattan but cant relate to it.
I worked it out this way
Assume,
t=1
b=2
Original = (1*2)^4= 16
New= (1*2*2)^4 = 256
% change= (change/Original)*100
=(240/16)*100
=1500
Where am I going wrong?
Thanks
New Cost C2=t2*b2^4....only b is doubled so t2=t1 and b2=2b1
C2=t2*(2b1)^4
=16(t1*b1^4)
=16C1
16 times C1=>1600% of C1
Ans D=1600
