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# Counting

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Director
Joined: 07 Jun 2004
Posts: 609

Kudos [?]: 966 [0], given: 22

Location: PA
Counting [#permalink]

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20 Aug 2010, 14:58
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3 couples need to be arranged for a group picture , and the couples cannot be separated how many arrangements is possible
_________________

If the Q jogged your mind do Kudos me : )

Kudos [?]: 966 [0], given: 22

Director
Status: Apply - Last Chance
Affiliations: IIT, Purdue, PhD, TauBetaPi
Joined: 17 Jul 2010
Posts: 679

Kudos [?]: 169 [0], given: 15

Schools: Wharton, Sloan, Chicago, Haas
WE 1: 8 years in Oil&Gas
Re: Counting [#permalink]

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20 Aug 2010, 15:36
relovchkin made me think again, i always have confusion as to whether 2^3 or 2! x 3.. in this case 3! is clear and then my thinking was that i can rearrange each couple in 2 ways, then there are 3 couples so it is 3! x 2 x 2 x 2.. When would 3! x 2! x 3 be right?
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Consider kudos, they are good for health

Kudos [?]: 169 [0], given: 15

Manager
Joined: 01 Jul 2010
Posts: 53

Kudos [?]: 62 [0], given: 15

Schools: LBS, Harvard, Booth, Stanford, ISB, NTU
WE 1: S/W Engineer
Re: Counting [#permalink]

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21 Aug 2010, 03:19
First consider the 3 couples each as single unit. Hence 3 couples can be arranged in 3! ways. And then for each of those 6 combination there are 8 ways in which individuals in a couple can be arranged.
Hence 6*8 = 48 ways.
Eg:
A,B,C are 3 couples.
6 ways to arrange them is:
ABC BCA CBA
ACB BAC CAB
Now if a1a2, b1b2, c1c2 are the individuals, then they can be arranged in 8 ways:
a1a2,b1b2,c1c2
a2a1,b1b2,c1c2
a1a2,b2b1,c1c2
a2a1,b2b1,c1c2
a1a2,b1b2,c2c1
a2a1,b1b2,c2c1
a1a2,b2b1,c2c1
a2a1,b2b1,c2c1
Similar arrangements are possible for the rest of the 5 couple arrangements.

Am I right in my explanation???

Kudos [?]: 62 [0], given: 15

Re: Counting   [#permalink] 21 Aug 2010, 03:19
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# Counting

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