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MBAlad
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d=2^64 p=2^3 p^d = 22 Aug 2006, 16:08
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d=2^64

p=2^3

p^d = ?



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MBAlad
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d=2^64 p=2^3 p^d = 22 Aug 2006, 17:00
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I dont know - dont have the answer for this one
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2times
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d=2^64 p=2^3 p^d = 22 Aug 2006, 17:36
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MBAlad
d=2^64

p=2^3

p^d = ?
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IMO....
p ^ d = 8^2^64 = 8^128 = 2^384
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gk3.14
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d=2^64 p=2^3 p^d = 22 Aug 2006, 18:45
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2^ 64 is not 128 I believe it is 8^(2^64)

or 8^18446744073709551616
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d=2^64 p=2^3 p^d = 22 Aug 2006, 19:58
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gk3.14
2^ 64 is not 128 I believe it is 8^(2^64)

or 8^18446744073709551616
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didn't get what u meant? a^b^c = a^bc right?
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gmatornot
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d=2^64 p=2^3 p^d = 22 Aug 2006, 20:19
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gk3.14
2^ 64 is not 128 I believe it is 8^(2^64)

or 8^18446744073709551616

didn't get what u meant? a^b^c = a^bc right?
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I think that all three of us are correct ...

e.g. 2^3^2 = 8^2 = 64 or 2^(3*2) = 2^6 = 64

2times got 2^384

I got 64^64 i.e. 2^6^64 = 2^384 which is the same value ! :-D
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d=2^64 p=2^3 p^d = 22 Aug 2006, 20:31
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Let's try an example

3^(2^3) is 3 raised to 8

If you could multiply the powers then it would be 3^6

I believe you can only multiply when you raise the power of the entire number so (3^2)^3 = 3^6, not when you raise the power of the exponent

Am i off base here?
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d=2^64 p=2^3 p^d = 22 Aug 2006, 20:45
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Shouldn't this just be:

2^(3x(2^64))
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ps_dahiya
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d=2^64 p=2^3 p^d = 23 Aug 2006, 00:32
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haas_mba07
Shouldn't this just be:

2^(3x(2^64))
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Exactly......
its not a question of a^b^c
its (a^b)^(c^d)
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MBAlad
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d=2^64 p=2^3 p^d = 07 Sep 2006, 19:00
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So does this mean the answer is 64^64 or 2^384 (I know they are the same)??????



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