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21 Apr 2023, 11:40
Kudos
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BrainLab
In order to win, we need either EXACTLY one more 4 or three of the same non-4 in a row. A lot of the "solutions" posted above ignore that word...
Four ways to win:
1. 4, not4, not4
1/6 * 5/6 * 5/6 = 25/216
2. not4, 4, not4
5/6 * 1/6 * 5/6 = 25/216
3. not4, not4, 4
5/6 * 5/6* 1/6 = 25/216
4. not4, samenot4, samenot4
5/6 * 1/6 * 1/6 = 5/216
25/216 + 25/216 + 25/216 + 5/216 = 80/216
Answer choice C.
11 Jun 2024, 22:08
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@BrainLabGiven: Daniel is playing a dice game in which a dice is rolled 5 times. If a number turns up exactly 3 times then the game is won. Daniel has thrown the dice two times and got number 4 both times.
Asked: What is the probability that Daniel will win the game ? (Note: the dice is an unbiased die with numbers 1 to 6)
Since only 1 throw of 4 is required in next 3 throws or any other number is required to be thrown in next 3 throws, the probability that Daniel will win the game = 3C1*5*5/6ˆ3 + 5C1/216= 75/216 + 5/216 = 80/216
IMO C
Asked: What is the probability that Daniel will win the game ? (Note: the dice is an unbiased die with numbers 1 to 6)
Since only 1 throw of 4 is required in next 3 throws or any other number is required to be thrown in next 3 throws, the probability that Daniel will win the game = 3C1*5*5/6ˆ3 + 5C1/216= 75/216 + 5/216 = 80/216
IMO C
06 Sep 2025, 09:06
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A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
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A member just gave Kudos to this thread, showing it’s still useful. I’ve bumped it to the top so more people can benefit. Feel free to add your own questions or solutions.
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